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san4es73 [151]
3 years ago
14

A survey indicated that 3 out of 5 doctors use brand X aspirin. If 2000 doctors were surveyed, how many used brand X?

Mathematics
1 answer:
Blizzard [7]3 years ago
8 0
2000(3/5)

6000/5

1200

So 1200 doctors used brand X
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A man bought a computer on hire purchase by making a down payment of$1500 and twelve monthly payments of $250 each. calculate th
lubasha [3.4K]

Answer:

$4500

Step-by-step explanation:

Given parameters:

   Down payment = $1500

   Monthly payment for twelve months  =$250

Unknown;

Total hire purchase price  = ?

Solution:

To find the total hire purchase price;

  Total hire purchase price  = Down payment + 12($250)

  Total hire purchase price  = $1500 + $3000

  Total hire purchase price  = $4500

7 0
2 years ago
When angles are complementary the sum of their measures is 90 degrees. Two complementary angles have measured of 2x-10 degrees a
Vinvika [58]

56° and 34°

complementary angles sum to 90° thus

3x - 10 + 2x - 10 = 90

5x - 20 = 90

add 20 to both sides of the equation

5x = 90 + 20 = 110

divide both sides by 5

x = \frac{110}{5} = 22

angle 2x - 10 = (2 × 22) - 10 = 44 - 10 = 34° and

angle 3x - 10 = (3 × 22) - 10 = 66 - 10 = 56°


3 0
3 years ago
Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer
agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0

g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]

This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

4 0
3 years ago
1. If A = {a, b, c, d}, B={c, d, e, f}, C={x, y, z} find (A-B)​
vitfil [10]

Answer

here

A={a,b,c,d}

B={c,d,e,f}

C={x,y,z}

A-B={e,f}

8 0
1 year ago
A certain recipe ask for 6/7 cup of granola. How much is needed to make 4/5 of a recipe?
Flauer [41]
Well the answer would be 24/35. hope that helped
8 0
2 years ago
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