How can I solve this?

Helpppppp pleaseeeeee !!!!!!!!! !!!!

Sergio [31]

Given:

The function is:

$f(x)=6x-3$

To find:

The inverse of the given function, then draw the graphs of function and its inverse.

Solution:

We have,

$f(x)=6x-3$

Step 1: Substitute $f(x)=y$ .

$y=6x-3$

Step 2: Interchange x and y.

$x=6y-3$

Step 3: Isolate variable y.

$x+3=6y$

$\dfrac{x+3}{6}=y$

Step 4: Substitute $y=g(x)$ .

$\dfrac{x+3}{6}=g(x)$

Therefore, the inverse of the given function is $g(x)=\dfrac{x+3}{6}$ and the graphs of these functions are shown below.

8 0

3 years ago

3(x - 4) < x - 8<br> Find x.

Phoenix [80]

Answer: x<2, (negative infinity, 2)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A piece of wire 13 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

Rom4ik [11]

The function you seek to minimize is

()=3‾√4(3)2+(13−4)2

f

(

x

)

=

3

4

(

x

3

)

2

+

(

13

−

x

4

)

2

Then

′()=3‾√18−13−8=(3‾√18+18)−138

f

′

(

x

)

=

3

x

18

−

13

−

x

8

=

(

3

18

+

1

8

)

x

−

13

8

Note that ″()>0

f

″

(

x

)

>

0

so that the critical point at ′()=0

f

′

(

x

)

=

0

will be a minimum. The critical point is at

=1179+43‾√≈7.345m

x

=

117

9

+

4

3

≈

7.345

m

So that the amount used for the square will be 13−

13

−

x

, or

13−=524+33‾√≈5.655m

5 0

3 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago

HELP PLEASE determine the number of real number solutions for the equation x^2+6x+9=0

brilliants [131]

Answer:

1 Answer->3

Step-by-step explanation:

To factor this out find the factors of 9 which add up to 6.

3 and 3 work therefore factor it out to

(x+3)(x+3)=0

Using Zero product property x is equal to -3

And there is only one answer which is 3

6 0

2 years ago