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zimovet [89]
3 years ago
10

Find the whole. 15% of ___is 12. Explain your method.

Mathematics
2 answers:
Wewaii [24]3 years ago
8 0
15% of ___ is 80. I cross multiplied by doing 15/100=12/x —> 45(x)=27(100)—> 45x=2700 —> 45x/45=2700/45 so x, or __, =60.
pav-90 [236]3 years ago
3 0

Answer:

Its 80

Step-by-step explanation:

80 x 15%=12

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3√7

Step-by-step explanation:

√63

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3 years ago
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ummmmmmmmmmmmmmmmmmmmmm

Step-by-step explanation:

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2 years ago
3 Caleb claims that when you multiply a number by 10, you can just write a 0 at the right end of the number. Caleb gives the exa
devlian [24]

Answer:

They are both correct

Step-by-step explanation:

It's interpretation of the concept. In common practice multiplying by 10 means you add a zero and that's what we teach 10 year olds. But what does adding a zero mean? It means adding a place value and that's what you learn when you are

So in both examples just add a decimal:

2.0 x 10 = 20.

0.2 x 10 = 2.0

In conclusion, it depends on the level of precision required in the discussion and the level of maturity as to who is correct in their examples. If you are teaching 3rd graders math, by all means you add a zero. If you are discussing physics you are shifting over a place value.

8 0
3 years ago
). If a, ß are zeroes of the quadratic polynomial p(x)=kx²+4x+4 such
natta225 [31]

Answer:

The values of k are 2/3 and -1

Step-by-step explanation:

Product of zeros = αβ= constant  / coefficient of x^2 =  4/k

Sum of zeros =α+β = - coefficient of x / coefficient of x^2= -4/k

Given

Consider a= α and b= β

(\alpha)^2 + (\beta)^2 = 24

(\alpha)^2 + (\beta)^2 can be written as (\alpha)^2 + 2(\alpha)(\beta) + (\beta)^2 if we add \pm 2 (\alpha)(\beta) in the above equation.

(\alpha)^2 + 2(\alpha)(\beta) + (\beta)^2 -2(\alpha)(\beta)

(\alpha + \beta)^2 -2(\alpha)(\beta)

Putting values of αβ and α+β

(\frac {-4}{k})^2 -2( \frac {4}{k}) = 24\\\frac {16}{k^2} - \frac {8}{k} = 24\\Multiplying\,\, the \,\, equation\,\, with\,\, 8K^2\\ 2 - k= 3K^2\\3k^2-2+k=0\\or\\3k^2+k-2=0\\3k^2+3k-2k-2=0\\3k(k+1)-2(k+1)=0\\(3k-2)(k+1)=0\\3k-2=0 \,\,and\,\, k+1 =0\\k= 2/3 \,\,and\,\, k=-1

The values of k are 2/3 and -1

8 0
3 years ago
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Trava [24]
27 pots..... I think. You have to divide the 81 in 81/4 by 3.
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