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Igoryamba
3 years ago
11

PLEASE HELP ME Which postulate or theorem proves that these two triangles are congruent?

Mathematics
2 answers:
vfiekz [6]3 years ago
7 0

Its the AAS Congruence Theorem. If you account for the vertical angles, the angle marked, and the one side marked it makes AAS. Hope it helped :))

tino4ka555 [31]3 years ago
7 0

Angle side angle congruence postulate. ASA

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The perpendicular bisectors of triangle RST intersect at K. Find KR
ivanzaharov [21]

Answer:

Step-by-step explanation:

Remark

The diagram is a mess of lines; you have to guess where that 12 belongs. Just to make the question a bit more interesting, I'm going to say the 12 belongs to the perpendicular.

If that's true you can find KT using Pythagorus. KT and RT are equal. (SSS)

So, let's go.

Givens

1/2 of ST = 1/2 32 = 16

12 is the leg of the small triangle KT and the third point where the perpenduclar line meets ST.

Solution

KT^2 = 16^2 + 12^2

KT^2 = 256 + 144

KT^2 = 400

KT = sqrt(400)

KT = 20

RK = KT because parts of a congruent triangle = parts of the other triangle containing the line (KT) that you are trying to find the length of.

7 0
3 years ago
I do not understand this
Ymorist [56]
Use this to help u :) to risk surface area

6 0
3 years ago
1+cos2A /1-cos2A=cotA.cotA​
Allisa [31]

Answer:

See Explanation

Step-by-step explanation:

formulae \: to \: be \: used :  \\  \cos 2 \theta = 2 { \cos}^{2}  \theta - 1 \\ and \\ \cos 2 \theta = 1 - 2 { \cos}^{2}  \theta  \\  \\ now \: let \: us \: prove \: the \: given \: trigonometrical \:  \\ identity. \\  \\  \frac{1 +  \cos2A}{1  -   \cos2A}  = \cot \: A. \cot \: A \\ LHS =  \frac{1 +  \cos2A}{1  -   \cos2A}  \\  \\  =  \frac{1 +2 { \cos}^{2}   A- 1 }{1 - (1  - 2 { \sin}^{2}   A)}  \\  \\ =  \frac{1 +2 { \cos}^{2}   A- 1 }{1 - 1   + 2 { \sin}^{2}   A}  \\  \\ =  \frac{2 { \cos}^{2}   A }{2 { \sin}^{2}   A}  \\  \\ =  \frac{{ \cos}^{2}   A }{ { \sin}^{2}   A}  \\  \\  =  { \cot}^{2} A \\  \\  =  { \cot} A .{ \cot} A \\  \\  = RHS \\  \\ hence \: proved.

6 0
3 years ago
A parachutist's speed during a free fall reaches 207 kilometers per hour. What is this speed in meters per second? At this speed
Mamont248 [21]
<span>The speed is 57.5 m/s and the parachutist will fall 1150 m in 20 seconds.

Explanation<span>:
We start out with the ratio 207 km/1 hr.

We know that 1 km = 1000 m; this means 207 km = 207*1000 = 207000 m. This gives us 207000 m/1 hr.

We know that 1 hr = 60 minutes, so we have 207000 m/60 min.

We also know that 1 min = 60 seconds, so 60 min = 60*60 = 3600 sec; this gives us 207000 m/3600 sec.

Dividing this, we get 57.5 m/s.

In 20 seconds, the parachutist will fall 57.5(20) = 1150 m.</span></span>
4 0
4 years ago
Read 2 more answers
Mr smith has 1,104 student photos to display around the school. He plans to put them on 48 posters boards with the same number o
Degger [83]

Answer:

23

Step-by-step explanation:

1104/48=23

6 0
3 years ago
Read 2 more answers
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