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Semmy [17]
3 years ago
13

A project is expected to create operating cash flows of $22,500 a year for three years. The initial cost of the fixed assets is

$50,000. These assets will be worthless at the end of the project. An additional $3,000 of net working capital will be required throughout the life of the project. What is the project’s net present value if the required rate of return is 10%?
Business
1 answer:
astra-53 [7]3 years ago
6 0

Answer:

Net Present Value = $58,188 - $53,000 = $5,188

Explanation:

Net Present Value = Net Cash Inflow - Net Cash Outflow

Computing Net Cash Inflow Discounted @10% PV factor for each year =  \frac{1}{(1 + r){^n}} Where, r = interest rate = 10%, and n = period that is for year 1 = 1 for year 2 = 2 and for year 3 = 3

Year            Cash Inflow           PV Factor        PV

1                    $22,500                0.909              $20,452.5

2                   $22,500                0.826              $18,585

3                   $22,500                0.751                $16,897.5

3                   $3,000                   0.751               $2,253 (Working capital will be realized at end of project)

Net Cash inflow                                                  = $58,188

Net Cash outflow = Cost of fixed asset + Cost of working capital initially incurred

                      = $50,000 +  $3,000 = $53,000

Net Present Value = $58,188 - $53,000 = $5,188

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Owners are not required to pay it to foreign workers.

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Owners must pay it to any worker regardless of its nationality.

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Which of the following is most likely a topic of discussion in macroeconomics?an increase in the price of a hamburgera decrease
otez555 [7]

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a decrease in the unemployment rate

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I hope my answer helps you

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The American Eagle chain of retail stores has a reputation as one of the "coolest" brands according to Teen Research Unlimited.
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Initially, you produce 100 boxes of jelly beans per time period. Then a new customer calls and places an additional order for je
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You should produce as long as the marginal cost per additional box is lower than the marginal revenue obtained by the additional box.

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5 0
3 years ago
Repair calls are handled by one repairman at a photocopy shop. Repair time, including travel time, is exponentially distributed,
wolverine [178]

Answer:

the average number of customers awaiting repairs = 0.30

the system utilization = 42

the amount of time that the repairman is not out on a call is  = 4.64 hours

the probability of two or more customers in the system = 0.1764

Explanation:

Given that :

Repair time, including travel time =  mean of 1.6 hours per call.

Requests for copier repairs = mean rate of 2.1 per eight-hour day

i.e mean rate R = 2.1/day

Time = 8 hours

thus; mean rate μ = 8 hours/ 1.6 hours = 5

(a)

Let the average number of customers awaiting repairs be I_i :

I_i = \dfrac{R^2}{\mu (\mu-R)}

I_i = \dfrac{2.1^2}{5 (5-2.1)}

I_i = \dfrac{4.41}{5 (2.9)}

I_i = \dfrac{4.41}{14.5}

\mathbf{I_i = 0.30}

the average number of customers awaiting repairs = 0.30

(b) Determine system utilization.

The system utilization is determined as follows:

\delta = \dfrac{R}{\mu}

\delta = \dfrac{2.1}{5}

{\delta = 0.42}

\mathbf{\delta = 42}

(c) The amount of time during an eight-hour day that the repairman is not out on a call is calculated as :

Percentage of Idle time = 1 - \delta

Percentage of Idle time = 1 - 0.42

Percentage of Idle time = 0.58

However during an 8 hour day; The amount of time that the repairman is not out on a call is = 0.58 × 8 = 4.64 hours

(d)

the probability of two or more customers in the system by assuming Poisson Distribution is:

P(N ≥ 2) = 1 - (P₀+ P₁)

where;

P₀ = 0.58

P₁ = 0.58  × 0.42 = 0.2436

P(N ≥ 2) = 1 - ( 0.58 + 0.2436)

P(N ≥ 2) = 1 - 0.8236

P(N ≥ 2) = 0.1764

Thus; the probability of two or more customers in the system is 0.1764

7 0
4 years ago
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