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Komok [63]
3 years ago
15

A ship is 15 miles due west of lighthouse A on the island of Hawaii. If lighthouse B is 6.2 miles due south of lighthouse A, wha

t is the bearing to the nearest tenth of a degree of the ship from lighthouse B? To the nearest tenth of a mile, how far is the ship from lighthouse B?
Mathematics
2 answers:
Ierofanga [76]3 years ago
6 0
I think its 6.2 miles
Airida [17]3 years ago
6 0

Answer:

67.5°

16.2 miles

Step-by-step explanation:

According to data, ship is at 15 miles due west to light house A.

Light house B is 6.2 miles due south of Light house A

Now,

                Ship______15 miles_____Light house A

                                                            ║

                                                            ║ 6.2 miles

                                                            ║  

                                                            Light house B

You can see that, if you draw an imaginary straight line from light house B to ship, it is forming a right angle triangle,

so, according to Pythagoras theorem,

(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2

We need to find hypotenuse,

Base = 6.2, Perpendicular = 15

So, H^2 = (15)^2 + (6.2)^2

H^2 = 225 + 38.44

H = 16.23 miles

now for rounding of to nearest 10th place

H = 16.2 miles

Now for angle of Ship from light house is

Cos^Ф = Base/Hypotenuse

Base = 6.2

Hypotenuse = 16.2

Cos^Ф = 6.2/16.2

Ф = 67.49°

After rounding off to the nearest tenth place

Ф = 67.5°

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Answer:The crystal structures of five 6-mercaptopurine derivatives, viz. 2-[(9-acetyl-9H-purin-6-yl)sulfan­yl]-1-(3-meth­oxy­phen­yl)ethan-1-one (1), C16H14N4O3S, 2-[(9-acetyl-9H-purin-6-yl)sulfan­yl]-1-(4-meth­oxy­phen­yl)ethan-1-one (2), C16H14N4O3S, 2-[(9-acetyl-9H-purin-6-yl)sulfan­yl]-1-(4-chloro­phen­yl)ethan-1-one (3), C15H11ClN4O2S, 2-[(9-acetyl-9H-purin-6-yl)sulfan­yl]-1-(4-bromo­phen­yl)ethan-1-one (4), C15H11BrN4O2S, and 1-(3-meth­oxy­phen­yl)-2-[(9H-purin-6-yl)sulfan­yl]ethan-1-one (5), C14H12N4O2S. Compounds (2), (3) and (4) are isomorphous and accordingly their mol­ecular and supra­molecular structures are similar. An analysis of the dihedral angles between the purine and exocyclic phenyl rings show that the mol­ecules of (1) and (5) are essentially planar but that in the case of the three isomorphous compounds (2), (3) and (4), these rings are twisted by a dihedral angle of approximately 38°. With the exception of (1) all mol­ecules are linked by weak C—H⋯O hydrogen bonds in their crystals. There is π–π stacking in all compounds. A Cambridge Structural Database search revealed the existence of 11 deposited compounds containing the 1-phenyl-2-sulfanyl­ethanone scaffold; of these, only eight have a cyclic ring as substituent, the majority of these being heterocycles.

Keywords: crystal structure, mercaptopurines, supra­molecular structure

Go to:

Chemical context  

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6-Mercaptopurine is a water insoluble purine analogue, which attracted attention due to its anti­tumor and immunosuppressive properties. The drug is used, among others, in the treatment of rheumathologic disorders, cancer and prevent

Step-by-step explanation:

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