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3 years ago

Which is the best estimate of the mass of a basketball? A. 6 grams B. 600 grams C. 6,000 grams or D. 60 kilograms?

Mathematics

1 answer:

Tom [10]3 years ago

5 0

A basketball is about B. 600 grams.

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Caroline buys a plant from the store that is 12 cm tall.

tangare [24]

Answer:

Height in w week = 12 + 2w

Step-by-step explanation:

Given:

Height of plant = 12 cm

Rate of plant growth = 2 cm per week

Find:

Equation

Computation:

Height in w week = Height of plant + (Rate of plant growth)(Number of week)

Height in w week = 12 + (2)(w)

Height in w week = 12 + 2w

8 0

3 years ago

A bag has 13 marbles in it. Seven of them are green, two of them are red, three of them are yellow, and one of them is blue. If

Inessa [10]

Answer:

The answer is c .85

Step-by-step explanation:

1. marbles that are not red/ total marbles

2. 11/13

3. 11/13= .846

4. .846 is rounded up to .85

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3 years ago

The probability of a team winning a volleyball tournament is 0.14.

mars1129 [50]

Answer:

0.14 as a percentage is 14%

4 0

3 years ago

Q=2p+1\2 compare the equation with y=mx+b

RSB [31]

<span>Q = y 2 = m p= x and 1/2 = + b :D
Anything with + ____ is the same as + b, and anything with a number and a variable after is equal to mx, and anything equal to something is the same as y =.
Hope I helped! c:</span>

8 0

3 years ago

3. university dean of students wishes to estimate the average number of hours students spend doing homework per week. The standa

gregori [183]

Answer:

A sample of 17 must be selected.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.96}{2} = 0.02$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.02 = 0.98$ , so Z = 2.054.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The standard deviation from a previous study is 4 hours.

This means that $\sigma = 4$

How large a sample must be selected if he wants to be 96% confident of finding whether the true mean differs from the sample mean by 2 hours?

A sample of n is required.

n is found for M = 2. So

$M = z\frac{\sigma}{\sqrt{n}}$

$2 = 2.054\frac{4}{\sqrt{n}}$

$2\sqrt{n} = 2.054*4$

Simplifying both sides by 2:

$\sqrt{n} = 2.054*2$

$(\sqrt{n})^2 = (2.054*2)^2$

$n = 16.88$

Rounding up:

A sample of 17 must be selected.

8 0

3 years ago