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zalisa [80]
3 years ago
7

How do you simplify -2( -1 - w )

Mathematics
2 answers:
kifflom [539]3 years ago
7 0
Distribute:
2-2x-w

regroup terms:
2-(-2w)

simplify brackets:
2+2w
iVinArrow [24]3 years ago
3 0
-2(-1-w)
-2(-1)-2(-w)
2*1+2w
2+2w
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The Richter scale measures the magnitude, M, of an earthquake as a function of its intensity, I, and the intensity of a referenc
expeople1 [14]

Answer:

The equation is = I = e^{4.8}

Step-by-step explanation:

As given ,

M - magnitude of an earthquake

I - intensity of earthquake

I₀ - intensity of a reference earthquake

The relation between the three is as follows :

M = log(\frac{I}{I0} )

As given -

M = 4.8,  I₀ = 1

⇒ 4.8 = log(\frac{I}{1}) = log(I)

⇒ 4.8 = log(I)

⇒I = e^{4.8}

So, the equation becomes I = e^{4.8}

8 0
3 years ago
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What is the answer in 8=2x+4 ​
Zielflug [23.3K]

Answer:

x = 2

Step-by-step explanation:

8 0
3 years ago
Holly works ina garage <br> Mr Bhakti brings his car
swat32

Answer:

298.788

Step-by-step explanation:

110+49.99+89 = 248.99

248.99 + 20%

= 298.788

6 0
3 years ago
Write the function in vertex form <br> y=-x^2-2x+7
Akimi4 [234]
I hope this helps you

4 0
4 years ago
What will be the value of
madreJ [45]

The expression as given doesn't make much sense. I think you're trying to describe an infinitely nested radical. We can express this recursively by

\begin{cases}a_1=\sqrt{42}\\a_n=\sqrt{42+a_{n-1}}\end{cases}

Then you want to know the value of

\displaystyle\lim_{n\to\infty}a_n

if it exists.

To show the limit exists and that a_n converges to some limit, we can try showing that the sequence is bounded and monotonic.

Boundedness: It's true that a_1=\sqrt{42}\le\sqrt{49}=7. Suppose a_k\le 7. Then a_{k+1}=\sqrt{42+a_k}\le\sqrt{42+7}=7. So by induction, a_n is bounded above by 7 for all n.

Monontonicity: We have a_1=\sqrt{42} and a_2=\sqrt{42+\sqrt{42}}. It should be quite clear that a_2>a_1. Suppose a_k>a_{k-1}. Then a_{k+1}=\sqrt{42+a_k}>\sqrt{42+a_{k-1}}=a_k. So by induction, a_n is monotonically increasing.

Then because a_n is bounded above and strictly increasing, the limit exists. Call it L. Now,

\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}a_{n-1}=L

\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}\sqrt{42+a_{n-1}}=\sqrt{42+\lim_{n\to\infty}a_{n-1}}

\implies L=\sqrt{42+L}

Solve for L:

L^2=42+L\implies L^2-L-42=(L-7)(L+6)=0\implies L=7

We omit L=-6 because our analysis above showed that L must be positive.

So the value of the infinitely nested radical is 7.

4 0
3 years ago
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