Answer:
Step-by-step explanation:
The swordfish swims at 68 miles per hour because 4•17=68
Answer:
y=3/4x-4 and ignore this stuff ejdndjsienensmsk
Answer:
1. More pollination process in the regular corn planted in field A than that of field B.
2. Low pest and insect attack on corn planted in field A compared to that of B.
Step-by-step explanation:
1. Pollination is the process in which a plant becomes fertilized, so as to produced seeds. The process requires some agent which could be; air, human, wind etc.
Therefore more pollination of the corn planted in field A than those in B would lead to more yield (ears of corn harvested) than that of B.
2. Pests and insects are agents which could reduce the yield of the corn after harvest. Comparing the two fields A and B, if the corn planted in field A were not affected by pests or insects, while those planted in B were affected, then more ears of corn would be harvested in field A.
Question #1
Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5.
So the y-intercept is 5.Part B:
The slope is 22.Part C:
y = mx + b
y = 22x + 5
We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10
The domain is 10.Question #2
Part A:
(2,255)
(5,480)
Standard form is Ax + By = C
Let's plug this into this form first:
Now, let's make it into Standard Form.
What, which is in the box, is your final answer. :)
Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:
Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)
Solution :
Given :
Sample mean,
Sample size, n = 129
Sample standard deviation, s = 8.2
a. Since the population standard deviation is unknown, therefore, we use the t-distribution.
b. Now for 95% confidence level,
α = 0.05, α/2 = 0.025
From the t tables, T.INV.2T(α, degree of freedom), we find the t value as
t =T.INV.2T(0.05, 128) = 2.34
Taking the positive value of t, we get
Confidence interval is ,
(32.52, 35.8)
95% confidence interval is (32.52, 35.8)
So with confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.
c. About of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.