15x + 28y = 116
x + y = 6
that would be ur system of equations
A horizontal translation is expressed by transforming
![f(x)\mapsto f(x+k)](https://tex.z-dn.net/?f=f%28x%29%5Cmapsto%20f%28x%2Bk%29)
If
is positive, the function is translated to the left. If
is negative, the function is translated to the right.
So, a 3-units left shift is given by
. So you have
![f(x)=2x^2-1 \implies f(x+3)=2(x+3)^2-1](https://tex.z-dn.net/?f=f%28x%29%3D2x%5E2-1%20%5Cimplies%20f%28x%2B3%29%3D2%28x%2B3%29%5E2-1)
Answer:
ln|sec θ + tan θ| + C
Step-by-step explanation:
The integrals of basic trig functions are:
∫ sin θ dθ = -cos θ + C
∫ cos θ dθ = sin θ + C
∫ csc θ dθ = -ln|csc θ + cot θ| + C
∫ sec θ dθ = ln|sec θ + tan θ| + C
∫ tan θ dθ = -ln|cos θ| + C
∫ cot θ dθ = ln|sin θ| + C
The integral of sec θ can be proven by multiplying and dividing by sec θ + tan θ, then using ∫ du/u = ln|u| + C.
∫ sec θ dθ
∫ sec θ (sec θ + tan θ) / (sec θ + tan θ) dθ
∫ (sec² θ + sec θ tan θ) / (sec θ + tan θ) dθ
ln|sec θ + tan θ| + C
Let x = the amount that Katie spent
Katie: x dollars
Stephanie: x-3 dollars
Brandy: 2x dollars
Together they spent $56, so the sum of these numbers should equal $56
x + (x-3) + 2x = 56
x + x + 2x - 3 = 56
4x = 59
x= 14.75
Katie spent $14.75