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3 years ago

Find the area and perimeter of a rectangle that is 14.5 meters by 5.8 meters

Mathematics

1 answer:

worty [1.4K]3 years ago

5 0

The perimeter is 40.6 meters and the area is 841 meters

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12.

shtirl [24]

Answer:5/8e

Step-by-step explanation:

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6 0

4 years ago

What is 792/336 in simplist form

Kipish [7]

If you divide first by 8 it gets 99/42

but you can divide again by 3

33/14

8 0

3 years ago

Read 2 more answers

Is there a even number and a odd number than mutiplys a odd number if so list 3 examples

s344n2d4d5 [400]

Answer:

Even

Step-by-step explanation:

Well if you have an odd number like 3, 5, 7, 9, and etc multiplied by an even number like 2, 4, 6, 8, and etc you will always get an even number

2 x 3 = 6 which is even 3+3

5 x 4 = 20 which is even 10+10

7 x 6 = 42 which is even 21+21

6 0

3 years ago

you consistently deposit 250.00 into a savings account on the 15th of each month, and the amount earns a 2.5 APR How much is the

frosja888 [35]

Answer:

Balance of savings account at the end of 3rd month = $753.13

Step-by-step explanation:

Balance at the end of 1st month :

Principal = $250 , Time = 1 month , n = 12 , APR = 2.5%

$\text{Compound Interest = }Principal\times (1+\frac{rate}{n\times 100})^{n\times Time}\\\\=250\times (1+\frac{2.5}{12\times 100})^{12\times \frac{1}{12}}\\\\=\$250.52$

Balance at the end of second month :

Principal = 250 + 250.52

= 500.52

Time = 1 month, APR = 2.5%, n = 12

$\text{Compound Interest = }500.52\times (1+\frac{2.5}{12\times 100})^{12\times \frac{1}{12}}\\\\=\$501.56$

Balance at the end of third month :

Principal = 250 + 501.56

= 751.56

Time = 1 month, APR = 2.5%, n = 12

$\text{Compound Interest = }751.56\times (1+\frac{2.5}{12\times 100})^{12\times \frac{1}{12}}\\\\=\$753.13$

Hence, Balance of savings account at the end of 3rd month = $753.13

6 0

3 years ago

a silkworm winds its cocoon out of one long silk fiber. to make silk thread, 3 to 10 of these silk fibers are unwound from their

Scorpion4ik [409]

Answer:

Possible lengths of the silk fibre 'x' are 100, 75, 60, 50 and 30 yards respectively.

Step-by-step explanation:

Let the length of the silk fiber = x yards.

Let the number of silk fibres = a.

It is given that the silk fibers between 3 to 10 yards are combined to form a silk thread of 300 yards.

So, we get the equation,

$ax=300$ , where $3\leq a\leq 10$

i.e. $x=\frac{300}{a}$ , $3\leq a\leq 10$

So, the possible values of 'a' are 3, 4, 5, 6 an 10.

Thus, the possible lengths of the silk fibre 'x' are 100, 75, 60, 50 and 30 yards respectively.

3 0

3 years ago