Which values are solutions to k-3/4 > –2? Check all that apply.

Mathematics

1 answer:

bulgar [2K]4 years ago

6 0

Answer:

k= -1

k= 0

k= 5

k= 8

Step-by-step explanation:

The given inequality is k-\frac{3}{4}>-2

We have to check which values lie in the solution set of this inequality.

In order to check the same we solve the inequality and check the possible values of x.

Add 3/4 to both sides

k>-2+\frac{3}{4}

Simplifying the right hand side

k>-\frac{5}{4}

Converting to decimal, we get

k>-1.25

Now, from the given values we choose those values which are greater than -1.25.

Hence, required values are

k= -1

k= 0

k= 5

k= 8

You might be interested in

A number line goes from negative 5 to positive 5. Point D is at negative 4 and point E is at positive 5. A line is drawn from po

Ronch [10]

Directed numbers are numbers that have either a positive or negative sign, which can be shown on a number line. Therefore, point F is Fifteen-halves of line segment DE.

A number line is a system that can show the positions of positive or negative numbers. It has its ends ranging from negative infinity to positive infinity. Thus any directed number can be located on the line.

Directed numbers are numbers with either a negative or positive sign, which shows their direction with respect to the number line.

In the given question, the distance between points D and E is 9 units. So that dividing 9 units in the ratio of 5 to 6, we have;

$\frac{5}{6}$ x 9 = $\frac{45}{6}$

= $\frac{15}{2}$

Therefore, the location of point F, which partitions the directed line segment from d to E into a 5:6 ratio is $\frac{15}{2}$ . Thus the answer is Fifteen-halves.

For further clarifications on a number line, visit: brainly.com/question/23379455

#SPJ1