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goldenfox [79]
2 years ago
12

A circle is drawn within a square as shown. What is the best approximation for the area of the shaded region? Use 3.14 to approx

imate pi.

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
8 0
<span>168.56 Square inches
</span>create an equation to solve
(area of the square) - (area of the circle) = Area of shaded region
 s^{2} -  \pi  r^2 = A
s= side of square (28 in)
r = radius (1/2 diameter. diameter = 28. 28/2= 14)
Substitute known values
28^{2} - (3.14) 14^2 = A
<span>784-615.44= 168.56 in^2</span>

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$1,045.21

Step-by-step explanation:

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What is the easiest to understand formula for solving 45 45 90 special right triangles?
alexgriva [62]

Step-by-step explanation:

45°, 45°, 90° triangle theorem states that:

Lengths of the sides opposite to the 45° angle are equal to one upon root two times of the length of hypotenuse.

Mathematically it can be expressed as:

length \: of \: sides \: opposite \: to \: 45 \degree \: \\  angle \\  =  \frac{1}{ \sqrt{2} }  \times length \: of \: hypotenuse.

4 0
3 years ago
Help with these math questions please help me thank you!
Reptile [31]

Step-by-step explanation:

1.(2,3)

2.No

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4.5

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6 0
3 years ago
How do I correctly solve this?
Gelneren [198K]
<h3>Answer: y = 14</h3>

===================================

Explanation:

The two angles involving x add up to 180 degrees. This is because they are same side interior angles (and because the horizontal lines are parallel)

So,

(angle BCF) + (angle EFC) = 180

(5x - 66) + (2x + 50) = 180

5x - 66 + 2x + 50 = 180

7x - 16 = 180

7x - 16+16 = 180+16 ... add 16 to both sides

7x = 196

7x/7 = 196/7 .... divide both sides by 7

x = 28

This will be used to help find y

Notice how the angles BCF and ACD are vertical angles, therefore they are congruent or the same measure

angle ACD = angle BCF

9y - 52 = 5x - 66

9y - 52 = 5*28 - 66 ..... replace x with 28 (since x = 28)

9y - 52 = 140 - 66

9y - 52 = 74

9y - 52+52 = 74+52 .... add 52 to both sides

9y = 126

9y/9 = 126/9 .... divide both sides by 9

y = 14

3 0
3 years ago
Read 2 more answers
(1 point) A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowi
Drupady [299]

Answer:

a. \dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

b. x(t) = 6\frac{2}{3} \cdot c \cdot t

c. c  = \dfrac{3}{8}  \ g/L

Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

The volume of brine added per minute = 5 liters per minute

The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

dx =  (5·c - 5·c/3)×dt = 20/3·c = 6\frac{2}{3} \cdot c \cdot dt

\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

b. The amount of salt, x after t minutes is given by the relation

\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

dx = 6\frac{2}{3} \cdot c \cdot dt

x(t) = \int\limits \, dx  = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt

x(t) = 6\frac{2}{3} \cdot c \cdot t

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10

6\frac{2}{3} \times c  =\dfrac{25 \ grams }{10}

c  =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} }  = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200}  \ g/L = \dfrac{3}{8}  \ g/L

c  = \dfrac{3}{8}  \ g/L

4 0
2 years ago
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