Answer:
Part 1)
------> 
Part 2)
------> 
Part 3)
------> 
Part 4)
------> 
Step-by-step explanation:
we know that
The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere
Part 1) we have

The area of the circle is equal to

so

Solve for r


Find the volume of the sphere
The volume of the sphere is

For 
substitute


Part 2) we have

The area of the circle is equal to

so

Solve for r


Find the volume of the sphere
The volume of the sphere is

For 
substitute


Part 3) we have

The area of the circle is equal to

so

Solve for r


Find the volume of the sphere
The volume of the sphere is

For 
substitute


Part 4) we have

The area of the circle is equal to

so

Solve for r


Find the volume of the sphere
The volume of the sphere is

For 
substitute


Let the angle of elevation be x, then
tan x = 1/12
x = arctan (1/12) = 4.8 degrees.
Answer:
24
Step-by-step explanation:
Answer:
0.018125r^2n
Step-by-step explanation: