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MatroZZZ [7]
3 years ago
11

Find the exact solution of -x2 +7x + 5 = 0 by using the Quadratic Formula.

Mathematics
1 answer:
jonny [76]3 years ago
7 0

Answer:

The answer to your question is:

x 1 = -0.65

x2 = 7.65

Step-by-step explanation:

Equation              -x² + 7x + 5 = 0

a = -1

b = 7

c = 5

Quadratic formula     x = -b ±√(b² -4ac) / 2a

                                   x = - 7 ± √(7² -4(-1)(5) / 2(-1)

                                   x = -7 ± √(49 + 20) / -2

                                  x = -7 ± √69 / -2

                                   x = - 7 ± 8.3 / -2

               x1 = -7 + 8.3 / -2                         x2 = -7 -8.3 / -2

               x 1 = -0.65                                  x2 = 7.65

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Answer:

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Answer:

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Solve for x. 5(x – 10) = 30 – 15x
SIZIF [17.4K]
Hey!


The first step to solving this problem would be to distribute the parenthesis. We do this so that we can get rid of the parenthesis.

<em>Original Equation :</em>
5 ( x - 10 ) = 30 - 15x

<em>New Equation {Changed by Distribution} :</em>
5x - 50 = 30 - 15x

The next step would be to 50 to both sides. The reason we do that is to get rid of the 50 that is on the left side of the equation.

<em>Old Equation :</em>
5x - 50 = 30 - 15x

<em>New Equation {Changed by Adding 50 to Both Sides} :</em>
5x = 80 - 15x

And now we would add 15x to both sides to get rid of the -15x on the right side of the equation.

<em>Old Equation :</em>
5x = 80 - 15x

<em>New Equation {Changed by Adding 15x to Both Sides} :</em>
20x = 80

Now we divide both sides by 20 to get x on it's own.

<em>Old Equation :</em>
20x = 80

<em>New Equation {Changed by Dividing Both Sides by 20} :</em>
\frac{20x}{20} = \frac{80}{20}

Finally, all we have to do is solve to find x.

<em>Old Equation :</em>
\frac{20x}{20} = \frac{80}{20}

<em>Solution {Old Equation Solved} :</em>
x = 4

<em>So, in the equation </em><span><em>5 ( x – 10 ) = 30 – 15x</em>,  x = 4.

Hope this helps!


- Lindsey Frazier ♥</span>
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2 years ago
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Answer:

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Step-by-step explanation:

Finding the common ratio (r) :

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Answer:

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