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MatroZZZ [7]
3 years ago
11

Find the exact solution of -x2 +7x + 5 = 0 by using the Quadratic Formula.

Mathematics
1 answer:
jonny [76]3 years ago
7 0

Answer:

The answer to your question is:

x 1 = -0.65

x2 = 7.65

Step-by-step explanation:

Equation              -x² + 7x + 5 = 0

a = -1

b = 7

c = 5

Quadratic formula     x = -b ±√(b² -4ac) / 2a

                                   x = - 7 ± √(7² -4(-1)(5) / 2(-1)

                                   x = -7 ± √(49 + 20) / -2

                                  x = -7 ± √69 / -2

                                   x = - 7 ± 8.3 / -2

               x1 = -7 + 8.3 / -2                         x2 = -7 -8.3 / -2

               x 1 = -0.65                                  x2 = 7.65

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lawyer [7]

Answer:

Step-by-step explanation:

You multiply 14.1 times 14.1 and you get 198.81 which is the closest to 200

3 0
3 years ago
Define the domain of the following
devlian [24]

The domain of the function or relation on the graph is { -2, -1, 0, 2 and 5}

<h3>What is the domain of a function?</h3>

The domain of the function is the set of input values of the graph

<h3>How to determine the domain of the function?</h3>

The function is represented by the set of relation or ordered pairs on the graph

The graph is given as an attachment

The ordered pairs in the relation on the graph are:

(x, y)  = (-2, -3), (-1, -1), (0, 3), (2, 1) and (5, 2)

Remove the y values in the above domain

x = -2, -1, 0, 2 and 5

The x values represent the domain of the function

And the domain of the function is the set of input values of the graph

Hence, the domain of the function or relation on the graph is { -2, -1, 0, 2 and 5}

Read more about domain at:

brainly.com/question/1770447

#SPJ1

7 0
2 years ago
What is an equation of the line that is perpendicular to -x+2y=4 and passes through the point (-2, 1)
Nana76 [90]

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line is

x + 2y = 4

2y = - x + 4

y = -x/2 + 4/2

y = - x/2 + 2

Comparing with the slope intercept form, slope = - 1/2

If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the given line.

Therefore, the slope of the line passing through (- 2, 1) is 2

To determine the intercept, we would substitute m = 2, x = - 2 and y = 1 into y = mx + c. It becomes

1 = 2 × - 2 + c = - 4 + c

c = 1 + 4 = 5

The equation becomes

y = 2x + 5

5 0
3 years ago
2x(x)=5<br> I need help
zhuklara [117]

Step-by-step explanation:

X interprets (0,0), (-5, 0) all you must do is divide 5 by 2 so 5÷2=2.5 that is your answer

6 0
3 years ago
What is the equation of the line that passes through the points (-3,5) (6,8)
Ratling [72]

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{8}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-3)}}}\implies \cfrac{3}{6+3}\implies \cfrac{3}{9}\implies \cfrac{1}{3}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-5=\cfrac{1}{3}(x+3)\implies y-5=\cfrac{1}{3}x+1\implies y=\cfrac{1}{3}x+6

6 0
2 years ago
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