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3 years ago

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Question 1 Answer not submitted Joseph cycled a distance of 4 miles in 45 minutes. What is the unit rate at which Joseph was cyc

ling? Answer Choices 11.25 miles per hour 5.33 miles per hour 4 miles per hour 3 miles per hour

1 answer:

Dafna11 [192]3 years ago

8 0

45 minutes / 4 miles = 11.25 mph. The correct answer choice would be A.

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What is the value of x? Round to the nearest hundredth.

jeyben [28]

Answer:

The correct answer is first option

X = 34.61

Step-by-step explanation:

<u>Points to remember</u>

<u>Trigonometric ratios</u>

Sin θ = Opposite side/Hypotenuse

Cos θ = Adjacent side/Hypotenuse

Tan θ = Opposite side/Adjacent side

From the figure we can see that a right angled triangle with base x and hypotenuse = 81.9.

One angle = 65°

To find the value of x

We have Cos θ = Adjacent side/Hypotenuse

Cos 65 = X/81.9

X = 81.9 * Cos 65

= 81.9 * 0.4226

= 34.61

Therefore X = 34.61

The correct answer is first option

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3 years ago

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Sana reaches her office 20 minutes late by

iris [78.8K]

Uh....I don’t think you finished the question yet lol

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3 years ago

Hello can anybody answer this to me

Helen [10]

What is this subject

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3 years ago

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A friend of mine is giving a dinner party. His current wine supply includes 9 bottles of zinfandel, 10 of merlot, and 12 of cabe

e-lub [12.9K]

Answer:

Step-by-step explanation:

From the given information:

The total number of wine = 9 + 10 + 12 = 31

(1)

The number of distinct sequences used for serving any five wines can be estimated by using the permutation of the number of total wines with the number of wines served.

i.e

= $^{31}P_5$

$=\dfrac{31!}{(31-5)!}$

$=\dfrac{31!}{(26)!}$

$=\dfrac{31\times 30\times 29\times 28\times 27\times 26!}{(26)!}$

= 20389320

(2)

If the first two wines served = zinfandel and the last three is either merlot or cabernet;

Then, the no of ways we can achieve this is:

= $^9P_2\times ^{22}P_3$

$= \dfrac{9!}{(9-2)!}\times \dfrac{22!}{(22-3)!}$

$= \dfrac{9!}{(7)!}\times \dfrac{22!}{(19)!}$

$= \dfrac{9*8*7!}{(7)!}\times \dfrac{22*21*20*19!}{(19)!}$

= 665280

(3)

The probability that no zinfandel is served is computed as follows:

Total wines (with zinfandel exclusion) = 31 - 9 = 22

Now;

the required probability is:

$= \dfrac{^{22}P_5 }{^{31}P_5}$

$= \dfrac{\dfrac{22!}{(22-5)!} } {\dfrac{31!}{(31-5)!} }$

$= \dfrac{\dfrac{22!}{17!} } {\dfrac{31!}{(26)! }}$

$= \dfrac{(\dfrac{22*21*20*19*18*17!}{17!})} {(\dfrac{31*30*29*28*27*26!}{(26)! })}$

= 0.1549

≅ 0.155

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3 years ago

Ok another one i managed to fit in one screenshot this time

nika2105 [10]

C none of the above

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