All categories

3 years ago

Help. please thanks so much

Mathematics

1 answer:

MatroZZZ [7]3 years ago

3 0

You multiply 12 with the number in the column

You might be interested in

WHAT THE HECK IS THE ANSWER TO THIS -(3x+y)+2(x-4y)

Gnom [1K]

Answer:

-x -9y

Step-by-step explanation:

-(3x+y)+2(x-4y)

-3x -y +2x -2*4y

-x -y -8y

-x -9y

7 0

3 years ago

Read 2 more answers

Awnser for brainliest

igor_vitrenko [27]

Answer:

A (c=1,900-163-259)

Step-by-step explanation:

This is right because this equation follows the PEMDAS rules in order to get the correct answer.

7 0

3 years ago

PLEASE ANSWER FAST

Burka [1]

Answer:

9.95 + 8.01p ≤ 50, so p ≤ 5

Step-by-step explanation:

So to set up the equation you must first add 9.95+ because every order has a shipping fee of 9.95

Then you put in 8.01 is less than or equal to 50 because p representing a number of players is being multiplied by the unit cost 8.01. Trace is also wants the total to be under 50 dollars

Finally p is less than or equal to 5 because if you put the value 5 in for p in the equation, the equation is true.

The whole equation is 9.95 + 8.01p ≤ 50, so p ≤ 5

5 0

3 years ago

Read 2 more answers

(35+27)÷4×12= what??

Slav-nsk [51]

We have to do BIMDAS

so starting with the brackets we do

35+27

which is 62

62÷4×12

then we work left to right for multiplication and division

62÷4

which is 15.5

then we finish with 15.5×12

which is 186

hope it helps.

8 0

3 years ago

Read 2 more answers

Solve using the quadratic formula 2x^2+x+67=0

telo118 [61]

Answer:

$\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Multiple Roots
Standard Form: ax² + bx + c = 0
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Root i = √-1

Step-by-step explanation:

Step 1: Define

Identify

2x² + x + 67 = 0

a = 2

b = 1

c = 67

Step 2: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1^2-4(2)(67)}}{2}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-1 \pm \sqrt{1-4(2)(67)}}{2}$
[√Radical] Multiply: $\displaystyle x=\frac{-1 \pm \sqrt{1-536}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-1 \pm \sqrt{-535}}{2}$
[√Radical] Simplify: $\displaystyle x=\frac{-1 \pm i\sqrt{535}}{2}$

3 0

3 years ago