The image is not attached with, but by reading the question it is obvious that the blue region lies inside the larger square and outside the smaller square. That is the region between the two squares is the blue region.
We know the dimensions of both squares, using which we can find the area of both squares. Subtracting the area of smaller square from larger one, we can find the area of blue square and further we can find the said probability.
Area of larger square = 8 x 8 = 64 in²
Area of smaller square = 2 x 2 = 4 in²
Area of blue region = 64 - 4 = 60 in²
The probability that a randomly chosen point lies within the blue region = Area of blue region/Total area available
Therefore, the probability that a point chosen at random is in the blue region = 60/64 = 0.9375
Answer:
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Step-by-step explanation:
Answer:
1.5
Step-by-step explanation:
-2,-1,0,1,2,3,4,5
Le quitamos un número hasta llegar al medio. En el medio hay dos números, el 1 y el 2. Pues tenemos que buscar el promedio de los dos (1+2=3 y 3÷2=1.5).
I Think The answer is c I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
The probability of it happening once is 1/5, since 10/50 simplifies to 1/5. Because the ticket goes back in the bag, the probability stays constant at 1/5.
For it to happen twice, you multiply the probability of it happening once, twice.
1/5 • 1/5 = 1/25 probability of it being Gary's name twice in a row.
