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leva [86]
3 years ago
14

Select all of the statements that apply to scarlet fever, to test your understanding of skin diseases caused by streptococcus py

ogenes. most common mode of transmission is droplet or direct contact virulence is due to the action of erythrogenic toxin virulence is due to the action of an exfoliative toxin it is characterized by a vesicular rash it can be prevented with live attenuated vaccine
Biology
2 answers:
Naddika [18.5K]3 years ago
4 0

Answer:

Scarlet fever or scarlatina is a bacterial infection usually caused by  <em>Streptococcus pyogenes</em><em>.</em>

This bacteria can be found in the mouth and nasal passage of human beings.

They produce poison or toxins which produce bright red rashes on the body.

Other symptoms may include Pastia's lines, strawberry tongue, fever, chills, red, sore and swollen throats, et cetera.

The infection can spread when a healthy individual comes in direct contact with infected droplets, mouth, nose, or eyes of an infected individual.

Virulence factors include lipoteichoic acid and M protein (attachment), hyaluronic acid capsule (inhibits phagocytosis), erythrogenic toxins (causes rash) et cetera.

The treatment is usually done with the help of antibiotics and other medicines to treat symptoms.

Presently, there is no vaccine available for this fever.

Thus, the correct statements would be:

  • caused by <em>Streptococcus pyogenes</em>.
  • most common mode of transmission is droplet or direct contact
  • virulence is due to the action of erythrogenic toxin
  • it is characterized by a vesicular rash

polet [3.4K]3 years ago
3 0
Scarlet fever or scarlatina is an infection for those people having sore throat. It's symptoms usually is a bright red rash with fever as well as sore throat. It affects children from 5-15 years old. It is cause by the streptococcus pyogenes. It's mode of transmission is droplet and direct contact and the virulence is cause by erythrogenic toxin.
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In an effort to control vegetation overgrowth, 108 rabbits are released in an isolated area free of predators. After 2 years, it
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Answer:

246

Explanation:

Increased amount / current population = 972

Amount released = 108

time(t) = 2years

Using the exponential growth function :

f(t) = A*g^t

Where g = growth rate

To obtain the growth rate = g

972 = 108 * g^2

g^2 = 972 / 108

g^2 = 9

g = 3

To determine population after 9 months :

9 months to years = (9/12) = 0.75

t = 0.75

f(0.75) = 108*(3^0.75)

f(0.75) = 108 * 2.2795070

f(0.75) = 246.18676

= 246

6 0
3 years ago
A sample of the tissue from an inflamed, pus-filled area on the lower leg is treated with KOH and stained with GMS. Under the mi
viva [34]

Answer:

chromoblastomycosis

Explanation:

Here is the complete question;. A sample of the tissue from an inflamed, pus-filled area on the lower leg is treated with KOH and stained with GMS. Under the microscope golden brown spheres are visible. What disease are these observations consistent with?

A) pityriasis

B) fungemia

C) chromoblastomycosis

D) mycetoma

E) sporotrichosis

Answer is

C) chromoblastomycosis

Chromoblastomycosis is a chronic fungal infection of the skin and the subcutaneous tissue caused by traumatic inoculation of a specific group of dematiaceous fungi (usually Fonsecaea pedrosoi, Phialophora verrucosa, Cladosporium carrionii, or Fonsecaea compacta) through the skin.

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Answer:

A

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