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Anna007 [38]
3 years ago
13

A necklace contains twenty-four spherical beads of silver, each having a radius of 0.5cm. The beads are to be coated, and the co

st of coating is $10 per cm2. What is the approximate total cost, to the nearest cent, for coating the beads?
Mathematics
1 answer:
Inessa [10]3 years ago
4 0

Answer:

$153

Step-by-step explanation:

To find the total cost, we have to calculate the area of one bead, then all of them:

Area of one bead = pi x r^2 = 3.14 x 0.5^2 = 3.14 x 0.25 = 0.765cm^2

Area of 20 beads = 0.765 x 20 = 15.3cm^2

Now, we are able to calculate the ultimate cost of coating:

If the cost is $10 per cm^2, then we have to find how much it costs to coat 15.3 cm^2.

15.3 x 10 = $153.

Hope this helps

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a bicycle tire is 28 inches in diameter. approximately how far does the bicycle move forward each time the wheel goes around? (u
belka [17]

ANSWER

88 \: inches

EXPLANATION

The given bicycle has a tyre that is 28 inches in diameter.

How far the bicycle moves forward each time the wheel goes around is the circumference of the bicycle tyre.

This is calculated using the formula:

C =\pi \: d

We substitute the diameter and

\pi =  \frac{22}{7}

C =  \frac{22}{7}  \times 28

This simplifies to

C =22 \times 4

88 \: inches

8 0
3 years ago
Read 2 more answers
Bill paid $45.35 in tax on a laptop that cost $589. About what percent sales tax did Bill pay?
Softa [21]

Answer:

267.1115

Step-by-step explanation:

3 0
3 years ago
Mathematicians 4: Who is Who?
larisa86 [58]

Answer:

a. x = -9 or x = -2

b. -5(x - 4)

c. x = -3 or x = 5

d. x = ±7

Step-by-step explanation:

a. First person;

y = x² + 11x + 18

y = x² + 9x + 2x + 18

y = x(x + 9) + 2(x + 9)

y = (x + 9)(x + 2)

y = x = -9 or x = -2

b. Second person;

y = -5x + 20

The common factor is 5.

y = -5(x - 4)

c. Third person;

y = x² - 2x - 15

y = x² - 5x + 3x - 15

y = x(x - 5) + 3(x - 5)

y = (x + 3)(x - 5)

y = x = -3 or x = 5

d. Fourth person;

y = x² - 49

Applying the difference of squares formula;

(a² - b²) = (a - b)(a + b)

y = x² - 49 = x² - 7² = (x - 7)(x + 7)

y = (x - 7)(x + 7)

y = x = ±7

6 0
3 years ago
Is it possible for two numbers to have a difference of 8 and a sum of 1?
topjm [15]

Answer: yes , it is possible

Step-by-step explanation:

Let the first number be x and the second number be y .Then , the sum of the two numbers will be x + y , and their difference will be x - y.

Combining the two , we have :

x + y = 1 ............................... equation 1

x - y = 8 ................................. equation 2

solving the system of linear equation by substitution method. From equation 1 , make x the subject of the formula ,

x = 1 - y ...................... equation 3

Substitute equation 3 into equation 2 ,

1 - y - y = 8

1 - 2y = 8

add 2y to both sides

1 = 8 + 2y

subtract 8 from both sides

1 - 8 = 2y

- 7 = 2y

divide through by 2

y = \frac{-7}{2}

y = - 3.5

substitute y = -3.5 into equation 3 to find the value of x , we have

x = 1 - y

x = 1 - ( - 3.5 )

x = 1 + 3.5

x = 4.5

Let us check :

x + y will be

4.5 + (-3.5) = 1

Also ,

x - y will be

4.5 - (-3.5)

⇒ 4.5 + 3.5 = 8

7 0
3 years ago
Makayla's local movie theater has a movie girl club that charges an annual resignation fee for $25 however movie tickets are dis
photoshop1234 [79]

Answer:

Step-by-step explanation:

C(m) = 6x + 25....the domain will be ur x value...and ur x value represents number of tickets bought......so the domain is best represented by :

whole numbers

it cant be integers because it cant be negative numbers

it cant be rational because it cannot include decimals..u cant buy part of a ticket

it cant be real because it cant include irrational numbers

6 0
3 years ago
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