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levacccp [35]
4 years ago
9

Solve for z:

Mathematics
2 answers:
antiseptic1488 [7]4 years ago
4 0

The first answer is 34. You just need to add 8 and 2 on one side. Then, add 24 to both sides to cancel out the -24 on the opposite side. At the same time, add z to both sides to cancel out the negative. That would lead z to equal 34.

The second question is 500. This is because 20% is 1/5 of 100%. If you multiply the 100 by 5 times, you get the 100% of that question.

Reptile [31]4 years ago
4 0
2+8-z = -24
10-z= -24
-z = -24-10
-z= -34
therefore
z=34


(20/x) ×100 = 100
20/x =1
therefore
x= 20
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Point G bisects the line segment FH. The length of FG is 16 less than 3 times the length of GH. What is the length of FH?
charle [14.2K]

Answer: FH = 16

<h2><u>PART I</u></h2><h2 />

Concept:

Bisect means to cut or divide something into two equal parts.

In mathematics, usually bisect means cutting a segment or an angle.

If you are still confused, you may refer to the attachment below for a graphical explanation or tell me.

Solve:

<u>Given information</u>

FG is 16 less than 3 times the length of GH

Let x be the length of GH

<u>Given expression</u>

FG = GH

<u>Set equation</u>

3x - 16 = x

<u>Add 16 on both sides</u>

3x - 16 + 16 = x + 16

3x = x + 16

<u>Subtract x on both sides</u>

3x - x = x + 16 - x

2x = 16

<u>Divide 2 on both sides</u>

2x / 2 = 16 / 2

x=8

--------------------------------------------------------------------------------------------------------------

<h2><u>PART II</u></h2><h2><u /></h2>

Concept:

In order to find the length of FH, we need to know the idea of the segment addition postulate.

The Segment Addition Postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Solve:

<u>Given information</u>

FG = GH = x

x = 8

<u>Given expression deducted from the segment addition postulate</u>

FH = FG + GH

<u>Substitute values into the expression</u>

FH = x + x

FH = 8 + 8

\boxed {FH=16}

Hope this helps!! :)

Please let me know if you have any questions

8 0
3 years ago
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