![y= 3 \,\,,\,\,x= -2 \,\,and\,\, y=3\,\,,\,\, x=2](https://tex.z-dn.net/?f=y%3D%203%20%5C%2C%5C%2C%2C%5C%2C%5C%2Cx%3D%20-2%20%5C%2C%5C%2Cand%5C%2C%5C%2C%20y%3D3%5C%2C%5C%2C%2C%5C%2C%5C%2C%20x%3D2)
Step-by-step explanation:
Solving the following system of equations:
![x^2-y=1\\2x^2+y^2=17](https://tex.z-dn.net/?f=x%5E2-y%3D1%5C%5C2x%5E2%2By%5E2%3D17)
Let
![x^2-y=1\,\,\,(1)\\2x^2+y^2=17\,\,\,(2)](https://tex.z-dn.net/?f=x%5E2-y%3D1%5C%2C%5C%2C%5C%2C%281%29%5C%5C2x%5E2%2By%5E2%3D17%5C%2C%5C%2C%5C%2C%282%29)
Putting value of x^2 in eq(2)
![x^2 = 1+y\\Putting\,\,value\,\,of\,\,x^2\,\,in\,\,eq(2)\\2(1+y)+y^2=17\\2+2y+y^2=17\\y^2+2y+2-17=0\\y^2+2y-15=0\\Factorizing:\\y^2-3y+5y-15=0\\y(y-3)+5(y-3)=0\\(y+5)(y-3)=0\\y+5=0 \,\,and \,\, y-3=0\\y = -5 \,\,and \,\, y=3](https://tex.z-dn.net/?f=x%5E2%20%3D%201%2By%5C%5CPutting%5C%2C%5C%2Cvalue%5C%2C%5C%2Cof%5C%2C%5C%2Cx%5E2%5C%2C%5C%2Cin%5C%2C%5C%2Ceq%282%29%5C%5C2%281%2By%29%2By%5E2%3D17%5C%5C2%2B2y%2By%5E2%3D17%5C%5Cy%5E2%2B2y%2B2-17%3D0%5C%5Cy%5E2%2B2y-15%3D0%5C%5CFactorizing%3A%5C%5Cy%5E2-3y%2B5y-15%3D0%5C%5Cy%28y-3%29%2B5%28y-3%29%3D0%5C%5C%28y%2B5%29%28y-3%29%3D0%5C%5Cy%2B5%3D0%20%5C%2C%5C%2Cand%20%5C%2C%5C%2C%20y-3%3D0%5C%5Cy%20%3D%20-5%20%20%5C%2C%5C%2Cand%20%5C%2C%5C%2C%20y%3D3)
Now, finding value of x
Putting y=-5
![x^2 = 1+y\\x^2=1-5\\x^2=-4\\Taking\,\,square\,\,root\\x= \pm2i](https://tex.z-dn.net/?f=x%5E2%20%3D%201%2By%5C%5Cx%5E2%3D1-5%5C%5Cx%5E2%3D-4%5C%5CTaking%5C%2C%5C%2Csquare%5C%2C%5C%2Croot%5C%5Cx%3D%20%5Cpm2i)
y=-5, x= 2i and y=-5 , x= -2i
Since we need to find x and y coordinates and its value cannot be in terms of i so we will not consider these as answer
Putting y=3
![x^2 = 1+y\\x^2=1+3\\x^2=4\\Taking\,\,square\,\,root\\x= \pm2](https://tex.z-dn.net/?f=x%5E2%20%3D%201%2By%5C%5Cx%5E2%3D1%2B3%5C%5Cx%5E2%3D4%5C%5CTaking%5C%2C%5C%2Csquare%5C%2C%5C%2Croot%5C%5Cx%3D%20%5Cpm2)
So, ![y= 3 \,\,,\,\,x= -2 \,\,and\,\, y=3\,\,,\,\, x=2](https://tex.z-dn.net/?f=y%3D%203%20%5C%2C%5C%2C%2C%5C%2C%5C%2Cx%3D%20-2%20%5C%2C%5C%2Cand%5C%2C%5C%2C%20y%3D3%5C%2C%5C%2C%2C%5C%2C%5C%2C%20x%3D2)
Keywords: system of equations
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A) -60 + (-300)+100 = -350
B) 50 - (-40) - (-2) = 92
Slope = 1/2 :)
rise over run (rise/run)
so... 2/4 = 1/2
hope this helps!
Answer:
A discrete function is a function with distinct and separate values. This means that the values of the functions are not connected with each other (this will be shown as a bunch of points that are not connected together).