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Anettt [7]
3 years ago
11

Three points, A, B, and C exists in space such that B is "between" A and C. It is known that AB=7, BC=4, and AC=9. Are points A,

B, and C collinear? Give a written explanation, supported by mathematical evidence, for your answer.
Mathematics
1 answer:
LenKa [72]3 years ago
7 0
Two or more points are said to be collinear if they lie on the same straight line.

Given a straight line XY, with a point P on the straight line between point X and Y, then
XP + PY = XY

From the question, it was given that AB = 7 and BC = 4, so if A, B, C are colinear, then
AB + BC = AC
i.e. 7 + 4 = 11

But, from the equation, AC = 9.

Therefore, points A, B and C are not collinear.
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Answer:

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Step-by-step explanation:

The box plot is split into 4 parts, the first 25% of it (1/4 of 100) is 0.

Q stands for quarter (1/4) so Q1=30.5 because of where the first dot hits, and Q3=60.5 because of where the 3rd dot hits.

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I hope this makes sense and helps you!

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3 years ago
1. Find the value of x.<br> 2. Find the value of y.
DiKsa [7]

Answer:

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2 years ago
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F(x) = -22 +19<br> Find f(3)
xz_007 [3.2K]
There is no x in the equation to replace 3 with
7 0
3 years ago
Does anyone know how to solve this?
Sonbull [250]
Sin is -sqroot3/2, cosine is 1/2, when ever you are given a point, the y value is always sin and x value is always cosine.
3 0
3 years ago
Reorder the numbers and combine like terms to simplify. 4.5 + 2 1/2 + 6.0 - 5 1/2
DanielleElmas [232]

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