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deff fn [24]
3 years ago
15

To determine the height of a television tower, a person stands 135 ft from its base and determines the angle of elevation to the

top of the tower to be 38 degrees. What is the height of the tower?
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

  105.5 ft

Step-by-step explanation:

The tangent ratio is the ratio of the side opposite an angle to the adjacent side in a right triangle. Here, the side opposite the angle is the tower height, and the adjacent side is the distance to the tower. Then the appropriate relationship is ...

  tan(38°) = (tower height)/(135 ft)

Multiplying by the denominator gives ...

  tower height = (135 ft)·tan(38°) ≈ 105.473 ft

The height of the tower is about 105.5 feet.

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The answer to this question?
vagabundo [1.1K]

Answer:

1. 59  2.90  4.31   3. Sorry I dunno

Step-by-step explanation:

1. the 59 degrees is the same.

2. It's a perfect angle

3. Sorry

4.180-90-59=31

4 0
2 years ago
a rectangle has a length of 5 cm and width 3 cm. a similar rectangle has length 7.25 cm what is the width in cm of this rectangl
zheka24 [161]
First Rectangle Area: 5 * 3=15
Second rectangle's width: 15/7.5=2
I think this is the ans 
4 0
3 years ago
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What are the solutions to the expression 4x2+11x−3
lina2011 [118]

Step-by-step explanation:

4x² + 11x - 3 = 0

(4x-1)(x+3) = 0

x = 1/4, -3

6 0
3 years ago
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What is the quotient of 2 1/4 and 5/8
Charra [1.4K]
If you would like to find the quotient of 2 1/4 and 5/8, you can calculate this using the following steps:

2 1/4 = 9/4

2 1/4 / 5/8 = 9/4 / 5/8 = 9/4 * 8/5 = 18/5 = 3 3/5

The correct result would be 3 3/5.
8 0
3 years ago
A sample of 15 commuters in Chicago showed the average of the commuting times was 33.2 minutes. If s = 8.3 minutes, find the 95%
OleMash [197]

Answer:

The 95% confidence interval of the true mean.

(29.4261 ,36.9739)

Step-by-step explanation:

<u>Step :- (i)</u>

Given sample size 'n' =15

sample of the mean x⁻ = 33.2

The standard deviation of the sample 'S' = 8.3

<u>95% of confidence intervals</u>

<u></u>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )<u></u>

<u>Step:-(ii)</u>

<u>The degrees of freedom γ=n-1 = 15-1=14</u>

The tabulated value t = 1.761 at 0.05 level of significance.

now substitute all possible values, we get

(33.2 - 1.761\frac{8.3}{\sqrt{15} } ,33.2+ 1.761\frac{8}{\sqrt{15} } )

After calculation , we get

(33.2-3.7739 , 33.2+3.7739

(29.4261 ,36.9739)

<u>Conclusion</u>:-

the 95% confidence interval of the true mean.

(29.4261 ,36.9739)

8 0
3 years ago
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