The poverty level cutoff in 1987 to the nearest dollar was $10787.
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How to find a midpoint?</h3>
The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is:
.
For solving this exercise, first you need plot the points in a chart. See the image.
Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).



The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar was $10787.
Read more about the midpoint segment here:
brainly.com/question/11408596
The cube root of 287496 is 66
Answer:
x = 5.5
Step-by-step explanation:
Given 2 secants intersecting the circle from a point outside the circle then
The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is
x(x + 14) = 6(6 + 12)
x² + 14x = 6 × 18 = 108 ( subtract 108 from both sides )
x² + 14x - 108 = 0 ← in standard form
with a = 1, b = 14 and c = - 108
Using the quadratic formula to solve for x
x = ( - b ±
) / 2a
= ( - 14 ±
) / 2
= ( - 14 ±
) / 2
= ( - 14 ±
) / 2
x =
or x = 
x = - 19.5 or x = 5.5 ( to 1 dec. place )
However x > 0 ⇒ x = 5.5