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melisa1 [442]
4 years ago
8

Please help I need an answer ASAP

Mathematics
1 answer:
KIM [24]4 years ago
5 0
The right one should be the second
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HELP ME PLS.......................TY
Tom [10]
M is correct, at the end your answer will be 5m
5 0
3 years ago
Identify the reflection rule in the given figure.
saul85 [17]

Answer: A) Reflection along the line y = -1

===========================================================

Explanation:

Point A is at (1,5). Point A' is at (1,-7).

Apply the midpoint formula to find the center of these two points.

You should get (1,-1) as that midpoint.

Follow these steps for B(-1,3) and B'(-1,-5) to get the midpoint (-1,-1)

Those midpoints we found are located on the mirror line. We only need two such points to plot it. Drawing a line through (1,-1) and (-1,-1) graphs the equation y = -1. This is the horizontal line through -1 on the y axis.

7 0
3 years ago
Solve -9z >/= -72 CHECK YOUR ANSWER
777dan777 [17]

Answer:

z ≤ 8

Step-by-step explanation:

-9z ≥ -72

Isolate the variable, z. Treat the ≥ as a equal sign, what you do to one side, you do to the other. Divide -9 from both sides. Note that when you divide a negative number, you will flip the sign:

(-9z)/-9 ≥ (-72)/-9

z ≤ (-72)/(-9)

z ≤ 8

z ≤ 8 is your answer.

~

8 0
3 years ago
Which equation is not a linear equation?
Bond [772]

Answer:

2/x + 3/y = 5

Step-by-step explanation:

A linear equation refers to any equation that can be written in the form;

ax+b=0 or y - mx -c = 0

The graph of a linear equation will always be a straight line; Vertical, horizontal or with a given degree of steepness (slope).

All the equations given are linear, except the last equation;

2/x + 3/y = 5. The exponents of the variables x and y is not 1 hence the equation is non-linear. Find the graph attached;

3 0
3 years ago
Find the area of the region bounded by the parabola y = 2x^2, the tangent line to this parabola at (4, 32), and the x-axis.
Anna [14]
I have a solution here that has a slight change in given where instead of <span>(4, 32), it is (3, 18). However, since the solution has provided explanations on each process, step-by-step, I believe that by thoroughly analyzing it, you might just answer this problem on your own!
</span>

f(x) = 2x² ← this is the parabola 

f(3) = 2 * 9 = 18 → the parabola passes through A (3 ; 18), so its tangent line too 


f'(x) = 4x ← this is the derivative 

…and the derivative is the slope of the tangent line to the curve at x 

f'(3) = 4 * 3 = 12 ← this is the slope of the tangent line to the curve at x = 3 


Equation of the tangent line 

The typical equation of a line is: y = mx + b → where m: slope and where b: y-intercept 

You know that the slope of the tangent line is 12. 

The equation of the tangent line becomes: y = 12x + b 

The tangent line passes through A (3 ; 18), so these coordinates must verify the equation of the tangent line. 

y = 12x + b 

b = y - 12x → you substitute x and y by the coordinates of the point A (3 ; 18) 

b = 18 - 36 = - 18 

→ The equation of the tangent line is: y = 12x - 18 


Intersection between the tangent line to the curve and the x-axis: → when y = 0 

y = 12x - 18 → when y = 0 

12x - 18 = 0 

12x = 18 

x = 3/2 

→ Point B (3/2 ; 0) 


Intersection between the vertical line passes through the point A and the x-axis: → when x = 3 

→ Point C (3 ; 0) 

The equation of the vertical line is: x = 3 


Area of the region bounded by the parabola y = 2x², the tangent line to this parabola at (3 ; 18), and the x-axis. 

= (area of the region bounded by the parabola y = 2x² and the x-axis) - (area of the triangle ABC) 

= [∫ (from 0 to 3) of the parabola] - [(xC - xB).(yA - yC)/2] 

= [∫ (from 0 to 3) 2x².dx] - [(xC - xB).(yA - yC)/2] 

= { [(2/3).x³] from 0 to 3 } - { [3 - (3/2)].(18 - 0)/2 } 

= [(2/3) * 3³] - { [(6/2) - (3/2)] * 9 } 

= [(2/3) * 27] - { [(3/2) * 9 } 

= 18 - (27/2) 

= (36/2) - (27/2) 

= 9/2 square unit
6 0
3 years ago
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