1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mariana [72]
3 years ago
7

The equation 2|3x−1|=10 has two solutions, one positive and one negative. Solve the equation to find the solutions.

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0

2|3x−1|=10\\\\ |3x-1|=5\\\\ 3x-1=5 \vee 3x-1=-5\\\\ 3x=6 \vee 3x=-4\\\\ x=2 \vee x=-\dfrac{4}{3}

You might be interested in
you want to draw an enlargement of a design that is printed on a card that is 4in by 5in. you will be drawing this design on an
IRINA_888 [86]
The answer is 1-3/5 in. by 10-5/8 in.
4 0
3 years ago
Read 2 more answers
An educational organization in California is interested in estimating the mean number of minutes per day that children between t
Hatshy [7]

Answer:

The critical value for a 98% CI is z=2.33.

The 98% confidence interval for the mean is (187.76, 194.84).

Step-by-step explanation:

We have to develop a 98% confidence interval for the mean number of minutes per day that children between the age of 6 and 18 spend watching television per day.

We know the standard deveiation of the population (σ=21.5 min.).

The sample mean is 191.3 minutes, with a sample size n=200.

The z-value for a 98% CI is z=2.33, from the table of the standard normal distribution.

The margin of error is:

E=z\cdot \sigma/\sqrt{n}=2.33*21.5/\sqrt{200}=50.095/14.142=3.54

With this margin of error, we can calculate the lower and upper bounds of the CI:

LL=\bar x-z\cdot\sigma/\sqrt{n}=191.3-3.54=187.76\\\\\\UL=\bar x+z\cdot\sigma/\sqrt{n}=191.3+3.54=194.84

The 98% confidence interval for the mean is (187.76, 194.84).

4 0
4 years ago
Heck did I do wrong!?!?! IXL sucks
zysi [14]

Answer:

∠G, ∠HGI, ∠IGH

Step-by-step explanation:

» <u>Concepts</u>

To name an angle, you MUST include the vertex either in the middle or have it standing by itself. To clarify, you can either call this angle ∠G, ∠HGI, or ∠IGH because they all include the vertex, G, in the middle or by itself. You put ∠HIG, which is incorrect because the vertex <u>is not </u><u>I</u>.

<u></u>

6 0
3 years ago
Are the ratios 25/45 and 15/27 proportional? show your work, explain
e-lub [12.9K]

Answer:

They are proportional

Step-by-step explanation:

Cross multiply, if the results are the same, they are proportional. If not, well then they're not proportional.

25 × 27 = 675

45 × 15 = 675

They have the same result

They are proportional

6 0
3 years ago
Work out the value of s
diamong [38]

Answer:

s=6

Step-by-step explanation:

s= 10(1/2)+ -2(1/2)^2

s= 5+ (-1)^2

s= 5+1

s=6

6 0
3 years ago
Read 2 more answers
Other questions:
  • What's the best way to study for a math test?
    9·2 answers
  • I designers adding a border around the edge of rectangular swimming pool he measures the pool and find out the length of the poo
    14·2 answers
  • Which of the number below belong to the set of integers <br><br>1. -4 <br><br>2. 0.5<br><br>3. 3
    12·2 answers
  • Given f(x)=3x-2 and g(x)=-1/3x +2/3, determine if g(x) and f(x) are inverse functions?
    9·1 answer
  • Please help This is due today help please ASAP
    12·2 answers
  • I need some serious help I have 12 minutes left PLZZZ help
    7·1 answer
  • Find the probability of landing on an even number when spinning the spinner below.
    13·1 answer
  • Thelma and David built a recycling bin that is 6 feet wide 12 feet long and 14 feet high . How much trash can fit inside of the
    6·2 answers
  • The image point of A after a translation right 4 units and down 4 units is the point B(12, – 7). Determine the coordinates of th
    13·1 answer
  • Cassandra works at a bookstore. Yesterday, she sold 18 hardcover books. The rest of the books she sold were paperback books. She
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!