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3 years ago

Write each sum as a product of two factors Problem= 3x+(2+x)+5*2

Mathematics

1 answer:

ivanzaharov [21]3 years ago

4 0

$3x+(2+x)+5*2 =3x+x+2+10=4x+12=4(x+3)$

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Solve for x and y<br> -2x-y=-9<br> 5x-2y=-9

Lisa [10]

we use equation 1 first.
-2x -y = -9

-y = -9 + 2x

y = 9 -2x

We substitute value of y in equation 2

5x - 2 (9 - 2x) = -9

5x -18 - 4x = -9

5x - 4x = -9 + 18

x = 18 -9

x = 9

We now find the value of y

-2x -y = -9

-2 (9) - y = -9

-18 - y = -9

-y = -9 + 18

y = 9 - 18

y = -9

6 0

3 years ago

Alicia's MP3 player contains 1,260 song. Given that 35% of the songs are rock songs and 20% of the songs are rap songs, how many

schepotkina [342]

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3 years ago

Suppose you are managing 16 employees, and you need to form three teams to work on different projects. Assume that all employees

valentina_108 [34]

Answer:

4380 ways

Step-by-step explanation:

We have to form 3 project of 16 employees, they tell us that the first project must have 5 employees, therefore we must find the number of combinations to choose 5 of 16 (16C5)

We have nCr = n! / (R! * (N-r)!)

replacing we have:

1st project:

16C5 = 16! / (5! * (16-5)!) = 4368 combinations

Now in the second project we must choose 1 employee, but not 16 but 11 available, therefore it would be to find the number of combinations to choose 1 of 11 (11C1)

2nd project:

11C1 = 11! / (1! * (11-1)!) = 11 combinations

For the third project we must choose 10 employees, but since we only have 10 available, we can only do a combination of this, since 10C10 = 1, therefore:

3rd project: 1 combination

The total number of combinations fro selecting 16 employees for each project would be:

4368 + 11 + 1 = 4380 combinations, that is, there are 4380 different ways of forming projects with the given conditions.

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3 years ago

What’s the value of x??

KengaRu [80]

Answer:

Step-by-step explanation:

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3 years ago

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