Nucleus, mRNA, Rough ER, Ribosome, Golgi Body, Cell Membrane.
This question is kind of tricky since a protein would be within the nucleus AS an mRNA sequence and within the rough ER WITHIN a ribosome.
Answer:
d. pxp +2pq
Explanation:
The formula for genotype frequency for a population in Hardy-Weinburg equilibrium is as under:
p² + 2pq + q² = 1
where, p = dominant allele
q = recessive allele
Here,
p² represents frequency of homozygous dominant genotype
2pq represents frequency of heterozygous genotype
q² represents frequency of homozygous recessive genotype
Also, although the genotypes p² & 2pq are different from each other yet phenotypically they both will collectively produce dominant trait i.e. free ear lobes not attached earlobes. So the term "p² + 2pq or pxp + 2pq" represents the frequency of the individuals who show the dominant phenotype in this particular population. Dominant phenotype will comprise 75% of the population.
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Did you remind<span> the </span>predicted phenotype ratio<span> and </span>children<span> of </span>dihybrid parents<span> that are </span>both right-handed<span> and </span>posses free ear lobes<span> - 2159873.</span>