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vichka [17]
3 years ago
13

An object with a mass of 3.0 g raises the level of water in a graduated cylinder from 25.1 mL to 33.1 mL. What is the density of

the object?
Mathematics
1 answer:
Free_Kalibri [48]3 years ago
7 0
8mL i'm pretty sure because you subtract 25.1 from 33.1
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A group of 4 people went to a movie. Each person bought a large drink and a small box of popcorn. They paid a total of $33.00 fo
MariettaO [177]

I'm pretty sure your answer should be $4.50 for each drink. I multiplied the price of the popcorn (3.75 including the tax) by 4, since there are 4 people, which gave me 15. Then take 15 out of 33.00 which gave me 18. Divide 18 by 4 (number of people) and get 4.5 or 4 1/2 which equals out to $4.50 for each drink.

3.75 · 4= 15

33.00 - 15= 18

18 ÷ 4= 4.5 or 4 1/2

Hope this helps! =^-^=

7 0
3 years ago
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to co
Sveta_85 [38]
<span>First find the area of the field
A=WL
A=(110m)(60m)
A=6,600m^2
Now turn the cm into m
becouse 100cm^3=1m^3
660,000,000cm^3=6,600,000m^3
Now find out how many times you can cover the filled
6,600,000m^3/6,600m^2=100m
So it will be 100m thick.
P.S. I'm assuming you meant you jest forgot the m for 110m.</span>
8 0
4 years ago
roberta deposited 4,790.23 into a saving account with an interest rate of 3.8% compunded twice a year. about how long will it ta
Margarita [4]
The answer to this question would be: 17 years
The <span>interest rate is 3.8% compounded twice a year. The function of the saving account amount would be:
f(x)= </span><span>4,790.23* (1+ 0.038/2)^2x
</span>f(x)= 4,790.23* (1.019)^2x

Then for f(x)= 9,000 the x value would be:
9,000= 4,790.23* (1.019)^2x
9,000/4,790.23= (1.019)^2x
1.8788= (1.019)^2x
<span>2x=34
</span>x=17
7 0
4 years ago
Read 2 more answers
Is there a right answer to this question
laila [671]

Answer:

answer C

Step-by-step explanation:

I had the same test question

6 0
2 years ago
Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t
Tresset [83]

Answer: The volume of largest rectangular box is 4.5 units.

Step-by-step explanation:

Since we have given that

Volume = xyz

with subject to x+2y+3z=9

So, let z=\dfrac{9-x-2y}{3}

So, Volume becomes,

V=xyz\\\\V=xy(\dfrac{9-x-2y}{3})\\\\V=\dfrac{9xy-x^2y-2xy^2}{3}

Partially derivative wrt x and y we get that

9-2x-2y=0\implies 2x+2y=9\\\\and\\\\9-x-4y=0\implies x+4y=9

By solving these two equations, we get that

x=3,y=\dfrac{3}{2}

So, z=\dfrac{9-x-2y}{3}=\dfrac{9-3-3}{3}=\dfrac{3}{3}=1

So, Volume of largest rectangular box would be

xyz=3\times \dfrac{3}{2}\times 1=\dfrac{9}{2}=4.5

Hence, the volume of largest rectangular box is 4.5 units.

4 0
4 years ago
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