The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
Answer:
Step-by-step explanation:
Answer:
17/80
Step-by-step explanation:
change 21 1/4 to a fraction
2125/10000 and simplfy
425/2000
85/400
17/80
Answer:
w ≤ -2
Step-by-step explanation:
The first point is on -2 and is going down the number line so w is less than -2 but since there is a closed circle, it would be w is less than or equal to -2 or w ≤ -2
Answer:
An arithmetic sequence has a constant difference between each term. ... A geometric sequence has a constant ratio (multiplier) between each term. An example is: 2,4,8,16,32,… So to find the next term in the sequence we would multiply the previous term by 2.
Step-by-step explanation:
Give me a brainiest, please.
