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Reptile [31]
3 years ago
8

How do you factor out the coefficient of the variable in the problem 3n-24

Mathematics
1 answer:
cestrela7 [59]3 years ago
7 0
3(n-8)
You make it so that the three is on the outside of the brakets and that you can FOIL to bring it back to how it used to be
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What are the solutions to the equation <br> 0=x^2-10x+10
d1i1m1o1n [39]
X: 5/4 ( forme différents): 1,25
4 0
3 years ago
What is the gcf of 64 and 72?
skad [1K]
<span>A factor is a divisor - a number that will evenly divide into another number. The greatest common factor of two or more numbers is the largest factor that both numbers have in common.One way to determine the greatest common factor is to find all the factors of the numbers and compare them.
The factors of 64 are 1, 2, 4, 8, 16, 32, and 64.
The factors of 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72.
The common factors are 1, 2, 4, and 8. Therefore, the greatest common factor is 8. 
The greatest common factor can also be calculated by identifying the common prime factors and multiplying them together.
The prime factors of 64 are 2, 2, 2, 2, 2, and 2.
The prime factors of 72 are 2, 2, 2, 3, and 3.
The prime factors in common are 2, 2, and 2, so the greatest common factor is 2 x 2 x 2 = 8.
SummaryA factor is a divisor - a number that will evenly divide into another number. The greatest common factor of two or more numbers is the largest factor that both numbers have in common. 



Summary:
The common factors of 64 and 72 are 1, 2, 4, and 8.
The greatest common factor of 64 and 72 is 8.

Or in the short term; the answer is 8</span>
8 0
3 years ago
Please help me with precalculus??<br>linear and angular speed
Anit [1.1K]
13)

there are 2π radians in 1 revolution, and there are 60 seconds in 1 minute, so keeping that in mind, then,

\bf \cfrac{4\underline{\pi} }{5~\underline{s}}\cdot \cfrac{rev}{2\underline{\pi} }\cdot \cfrac{60~\underline{s}}{min}\implies \cfrac{4\cdot 60~rev}{5\cdot 2~min}\implies \cfrac{240~rev}{10~min}\implies 24\frac{rev}{min}

14)

 \bf \textit{linear velocity}\\\\&#10;v=rw\quad &#10;\begin{cases}&#10;r=radius\\&#10;w=angular~speed\\&#10;----------\\&#10;v=32\frac{m}{sec}\\&#10;w=100\frac{rev}{min}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\textit{let's convert \underline{w} to }\frac{radians}{sec}

\bf \cfrac{100~\underline{rev}}{\underline{min}}\cdot \cfrac{2\pi }{\underline{rev}}\cdot \cfrac{\underline{min}}{60~sec}\implies \cfrac{100\cdot 2\pi }{60~sec}\implies \cfrac{10\pi }{3~sec}\implies \cfrac{10\pi }{3}\frac{radians}{sec}\\\\&#10;-------------------------------\\\\&#10;v=rw\implies \cfrac{v}{w}=r\implies \cfrac{\frac{30~m}{sec}}{\frac{10\pi }{3~sec}}\implies r=\cfrac{30~m}{\underline{sec}}\cdot \cfrac{3~\underline{sec}}{10\pi }&#10;\\\\\\&#10;r=\cfrac{90}{10\pi }m

15)

what is the radians per seconds "w" in revolutions per minute?  just another conversion like in 13)

\bf \cfrac{\underline{\pi} }{3~\underline{sec}}\cdot \cfrac{rev}{2\underline{\pi }}\cdot \cfrac{60~\underline{sec}}{min}\implies \cfrac{60 ~rev}{3\cdot 2 ~min}\implies \cfrac{60 ~rev}{6 ~min}\implies 10\frac{rev}{min}
4 0
4 years ago
Simplify quantity x squared plus 6 x plus 8 end quantity over quantity x plus 2
Novosadov [1.4K]

Simplifying quantity x squared plus 6 x plus 8 end quantity over quantity x plus 2 we get x+4

Option d is correct.

Step-by-step explanation:

We need to simplify quantity x squared plus 6 x plus 8 end quantity over quantity x plus 2.

Writing in mathematical form:

\frac{x^2+6x+8}{x+2}

Solving:

Factorizing the numerator:

\frac{x^2+6x+8}{x+2}\\=\frac{x^2+4x+2x+8}{x+2}\\=\frac{x(x+4)+2(x+4)}{x+2}\\=\frac{(x+2)(x+4)}{x+2}\\Cancelling\,\,x+2\,\,forom\,\,numerator\,\,and\,\,denominator:\\=x+4

So simplifying quantity x squared plus 6 x plus 8 end quantity over quantity x plus 2 we get x+4

Option d is correct.

Keywords: Simplifying Expressions

Learn more about Simplifying Expressions at:

  • brainly.com/question/4786449
  • brainly.com/question/2166248
  • brainly.com/question/7014769

#learnwithBrainly

5 0
3 years ago
consider these graphs: Eric thinks the equation y=(x-3)^2 will match the blue graph. Jenney thinks it will match the red graph.
Dimas [21]

Answer: Jenny

Step-by-step explanation:

By subtitue Y = 0

0=(x-3)^2

And you get 3

3 0
3 years ago
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