As per the given question, the expression of the function
is as:

Now, as per the definition of zeros, the zero is that value of x which when plugged into the function should make the function zero (it is also called "making the function vanish"). <u>In our case, plugging in "zero values" of x should make the numerator zero without making the denominator zero.</u> Now, if we plug in the given values of x, which are x=-1, x=2 and x=4 in the function we see that the <u>numerator does not become a zero but the denominator does</u>.
Thus, x=-1, x=2 and x=4 are not the zeros of the function and therefore, Sue is wrong. However, we do have discontinuities at the aforementioned values of x because the denominator becomes a zero at those points and as per the definition of a discontinuity the denominator should be a zero at that point. Therefore, Ed is correct.
Answer:
29400
Step-by-step explanation:
Im pretty sure
Answer:
When dividing the numbers 1-8 by 9, we get whatever number was divided as a decimal in repeating form. For example, 2/9 = 0.22222...
<em>Brainliest, please! I'm almost an Ace!</em>
Step-by-step explanation:
1/9 = 0.11111...
2/9 = 0.22222...
3/9 = 0.33333...
4/9 = 0.44444...
5/9 = 0.55555...
6/9 = 0.66666...
7/9 = 0.77777...
8/9 = 0.88888...
Answer:
7
Step-by-step explanation:
Using Pythagoras' identity on the right triangle
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
let x be the other leg, then
x² + 4² = (
)²
x² + 16 = 65 ( subtract 16 from both sides )
x² = 49 ( take the square root of both sides )
x =
= 7
That is the other leg is 7 units