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4 years ago

Use algebraic rules of equations to predict the solution type to the system of equations. Include all of your work for full

Mathematics

1 answer:

kherson [118]4 years ago

7 0

Answer:

X + 2X - 1 = -4 => X = -1

=> Y = -3

Step-by-step explanation:

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The Robotics Manufacturing Company operates an equipment repair business where emergency jobs arrive randomly at the rate of thr

cluponka [151]

Answer:

The correct answer is:

$\lambda=0.375 \ jobs \ per \ hour$
$\mu=0.5 \ jobs \ per \ hour$

Step-by-step explanation:

The given values are:

Service time varies,

Repair time = 2 hours

Standard deviation = 1.5 hours

Robotics uses per hour cost,

= $35

Company's cost per hour,

= $28

(a)

⇒ Arrival rate = Jobs per hours

then,

= $\frac{8 \ hours}{3 \ jobs}$

= $2.666 \ hours \ per \ job$

The jobs per hour will be:

⇒ $\lambda=\frac{1}{2.666}$

$=0.375$

(b)

⇒ Service rate = jobs per hour

then,

μ = $\frac{1 \ repair \ job}{2 \ hours}$

= $0.5 \ jobs$

7 0

3 years ago

Sin(42) = cos(x) <br> Solve for x

mariarad [96]

Answer:

X = 48

Step-by-step explanation:

When you type sin(42) in your calculator it will give you something around 0.669.

If you try reverse sinus sin-1(0.669) it will give you 42.

Therefore you can say that:

Cos(x) = 0.669

So you can reverse the cos to get your answer

Cos-1(0.669) = 48

Cos-1 (sin(42))

3 0

3 years ago

Michael and his wife are each starting a saving plan. Michael will initially set aside $75 and then add $50.85 every week to the

lana [24]

Answer:

T = 75 + 116.9*N

Step-by-step explanation:

We have that the equation for Michael's savings is:

A = 75 + 50.85*N, where N is the number of weeks

And we have that the equation for his wife's savings is:

B = 65.95*N.

So, to find the total amount saved using both plans combined (T), we have to sum A and B:

T = A + B = 75 + 50.85*N + 65.95*N = 75 + 116.9*N

So the equation that relates T to N is:

T = 75 + 116.9*N

5 0

4 years ago

Read 2 more answers

The stem and lead plot shows data from a set of size 80 what are the median and mode

atroni [7]

Are there any more numbers to this problem ? a picture of the data

3 0

3 years ago

Read 2 more answers

A survey of 80 randomly selected companies asked them to report the annual income of their presidents. Assuming that incomes are

Artyom0805 [142]

Answer:

The 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

Step-by-step explanation:

The information provided is:

$n=80\\\sigma=30,000\\\bar x=585062.50\\\text{Confidence level} = 90\%$

The critical value of <em>z</em> for 90% confidence level is, 1.645.

Compute the 90% confidence interval estimate of the mean annual income of all company presidents as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\\\\=585062.50\pm 1.645\times\frac{30000}{\sqrt{80}}\\\\=585062.50\pm5517.50\\\\=(579545, 590580)$

Thus, the 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

This interval implies that there is 90% probability that the true mean annual income of all company presidents is within this interval.

4 0

3 years ago