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3 years ago

Absolute value to show the distance between -70 and 15

Mathematics

1 answer:

castortr0y [4]3 years ago

7 0

To find the absolute value, change all into positives, and add them

|-70| + 15 = answer

|-70| = 70

70 + 15 = 85

The distance in the number line between -70 and 15 is 85

85 is your answer

hope this helps

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PLEASE HELP!

Leona [35]

Answer:

The initial temperature of the object was 37.6

Step-by-step explanation:

we have

$f(t)=Ce^{(-kt)} +20$

where

f(t) represent the temperature of the object in degree Celsius

t is the time in minutes

Find the value of the constant C

we have the ordered pair (4,35)

substitute in the equation and solve for C

$35=Ce^{(-0.0399*4)} +20\\Ce^{(-0.0399*4)}=15\\C=15/e^{(-0.0399*4)}\\C=17.6$

Find the initial value of the object

we know that

The initial temperature is the value of f(t) when the value of t is equal to zero

For t=0

$f(0)=(17.6)e^{(-k*0)} +20\\f(0)=17.6 +20\\f(0)=37.6$

therefore

The initial temperature of the object was 37.6 (I not include units)

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3 years ago

The ratio of the sum of my favorite number and 9 to 15 is the same as the ratio of 3 to 5. What is my favorite number?

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Let

x---------> my favorite number

we know that

(x+9)/15=3/5------> 5*(x+9)=15*3-----> divide by 5 both sides----> (x+9)=3*3

x+9=9------> x=0

therefore

the answer is

My favorite number is 0

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