Answer:
(-1, 4)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
10x + 6y = 14
-x - 6y = -23
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Elimination</em>
- Add 2 equations together: 9x = -9
- Divide 9 on both sides: x = -1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: -x - 6y = -23
- Substitute in <em>x</em>: -(-1) - 6y = -23
- Multiply: 1 - 6y = -23
- Subtract 1 on both sides: -6y = -24
- Divide -6 on both sides: y = 4
102, first you subtract 1 from 4 so thats 3 and then you add the 32 and 2 so now all you have to do is multiply the results of 4-1 and 32+2
7/5 - 10/5 = -3/5
I hope this helps.
You multiply the GCF of the numerical part 3 and the GCF of the variable part x^2y to get 3x^2y
Answer:
10 cups
Step-by-step explanation:
1/4 cup times 4 is 1 cup
1/4 cup times 8 is 2 cups
now you have your two cups and you need two more 1/4 to make 2/4
