5 cans need to be bought. There are three servings in each can so you divide 15 by 3.
Each football is sold for $9.95. To make one of these football costs $7.10.
There is a profit of $2.85. Divide 11,400 by 2.85 to see how many footballs would have to sell to break even.
11,400 / 2.85 = 4000.
4000 footballs would have to be sold to break even.
Answer:
10%
Step-by-step explanation:
The change is 90-100 = -10. As a percentage of the original amount, that is ...
-10/100 × 100% = -10%
The change from 100 to 90 is a reduction of 10%.
Answer: The points are, the top left one, (21,3) and the one on the bottom is (6, 12)
Step-by-step explanation: For the slope, we label one of the points, with y or x. For example, (21, 3) we would label 21 either y1 or x1. Say we put y2, then 3 would be x2. Moving on, (6,12) this time we could label 6 as either y1 or x1. Same thing, but this time we are going to label 6 as y1 and 12 x1. Again, it’s DOES NOT matter what you label them as.
Now to solve it, remember y numbers always go on top! M which is slope. M = y2 - y 1 / x2 - x 1 or with the numbers M = 21 - 6 / 12 - 3 = 15/9 simplified = 5/3
Answer:
A - 90 units
B = 0 units
Step-by-step explanation:
Here we have two models A and B with the following particulars
Model A B (in minutes)
Assembly 20 15
Packing 10 12
Objective function to maxmize is the total profit
where A and B denote the number of units produced by corresponding models.
Constraints are
These equations would have solutions as positive only
Intersection of these would be at the point
i) (A,B) = (60,40)
Or if one model is made 0 then the points would be
ii) (A,B) = (90,0) oriii) (0, 90)
Let us calculate Z for these three points
A B Profit
60 40 1040
90 0 1080
0 90 720
So we find that optimum solution is
A -90 units and B = 0 units.
