is a difference of squares with a factor 2x+5
because when we factorize we get
Answer:
second choice
Step-by-step explanation:
The given sums ∑ have j = 1, j = 2, j = 3, j = 4, j = 5
Consider first j = 1 and substitute in the answers to see if we get the first term of the series -3
✅
2·1 - 5 = 2-5 = -3 ✅
3·1 - 6 = 3-6 = -3 ✅
❌
We see that last choice gives us as first term to be 1 not -3 so eliminate that possibility.
Consider now j = 2 and substitute in the answers to see if we get the second term of the series -1
✅
2·2 - 5 = 4-5 = -1 ✅
3·2 - 6 = 6-6 = 0 ❌
We see that third choice gives us as second term to be 0 not -1 so eliminate that possibility.
Consider now j = 3 and substitute in the answers to see if we get the third term of the series 1
❌
2·3 - 5 = 6-5 = 1 ✅
We see that first choice gives us as third term to be -1/3 not 1 so eliminate that possibility.
Now we are left with the second choice as the only possibility.
B. looks like the way to go.
Answer:
B- All real numbers less than 0
Step-by-step explanation:
Trust me.. Hope this helped
<span>you must make there be a common denominator(lower number) so 9/10*3(otherwise known as 3/3)=27/30 1/3*10(otherwise known as 10/10=10/30 now we do the math 27/30-10/30=17/30 when you add or subtract fractions you always find a common denominator then only add or subtract the numerator (top number)</span>