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Rina8888 [55]
4 years ago
14

Which value of y would make OP || LN ?

Mathematics
1 answer:
guajiro [1.7K]4 years ago
3 0
Remark
All you need do is assume the small triangle is similar to the large one. MO:ML :: MP:MN must be solved.

Givens
MO = 28
ML = 28 + 14
MP = y
MN = y + 18

Equation
28:28+14 :: y: y + 18

Solve
28/42 = y / (y + 18)
28*(y + 18) = 42y        Remove the brackets
28y + 18*28 = 42y
28y + 504 =  42y         Subtract 28y from both sides.
504 = 42y - 28y
504 = 14y                    Divide by 14
504/14 = y
y = 36


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3 years ago
ABC and EDC are straight lines. EA is parallel to DB. EC = 8.1 cm. DC = 5.4 cm. DB = 2.6 cm. (a) Work out the length of AE. cm (
harkovskaia [24]

By applying the knowledge of similar triangles, the lengths of AE and AB are:

a. \mathbf{AE = 3.9 $ cm}\\\\

b. \mathbf{AB = 2.05 $ cm} \\\\

<em>See the image in the attachment for the referred diagram.</em>

<em />

  • The two triangles, triangle AEC and triangle BDC are similar triangles.
  • Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.

<em>This implies that</em>:

  • AC/BC = EC/DC = AE/DB

<em><u>Given:</u></em>

EC = 8.1 $ cm\\\\DC = 5.4 $ cm\\\\DB = 2.6 cm\\\\AC = 6.15 $ cm

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>

EC/DC = AE/DB

  • Plug in the values

\frac{8.1}{5.4} = \frac{AE}{2.6}

  • Cross multiply

5.4 \times AE = 8.1 \times 2.6\\\\5.4 \times AE = 21.06

  • Divide both sides by 5.4

AE = \frac{21.06}{5.4} = 3.9 $ cm

<u>b. </u><u>Find the length of </u><u>AB:</u>

AB = AC - BC

AC = 6.15 cm

To find BC, use AC/BC = EC/DC.

  • Plug in the values

\frac{6.15}{BC} = \frac{8.1}{5.4}

  • Cross multiply

BC \times 8.1 = 6.15 \times 5.4\\\\BC = \frac{6.15 \times 5.4}{8.1} \\\\BC = 4.1

  • Thus:

AB = AC - BC

  • Substitute

AB = 6.15 - 4.1\\\\AB = 2.05 $ cm

Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:

a. \mathbf{AE = 3.9 $ cm}\\\\

b. \mathbf{AB = 2.05 $ cm} \\\\

Learn more here:

brainly.com/question/14327552

3 0
3 years ago
The distance between Joshua's home and school is 800 m. Joshua takes 5 min to walk
Fynjy0 [20]

Answer:

= 0.38 m/s

Step-by-step explanation:

▪Total distance = 800 m

5 min = 100 m

▪Remaining distance = 800 - 100 = 700 m

20 min = 700 m

▪Total time taken = 20 + 10 + 5 = 35 min

If 1 min = 60 sec

What about 35 min = ?

= 35 x 60

= 2100 sec

▪Average speed = TD ÷ TT

= 800 ÷ 2100

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7 0
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