We can solve this system of equations through the elimination method. First we create two equations, with x as the adult tickets and y as the child tickets. (3x + 1y = 201) (2x + 3y = 239)
You can now eliminate the x variable from both equations by multiplying them by a number so they become factors of each other. 2(3x+ 1y= 201) -3(2x+ 3y=239)
Our new equations- We can now remove the x from the equations and solve for y. (6x+ 2y= 402) (-6x -9y= -717)
(2y = 402) +(9y= -717) = (-7y= -315) (y=45) So the price of a child ticket is $45.
Pick any of the equations, and replace y with 45 to solve for x. (3x + 1y = 201) (3x + 1(45) = 201) (3x = 156) x= 52 The price of an adult ticket is $52.
