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3 years ago

How do you eat a proper Oreo?

Mathematics

2 answers:

Sauron [17]3 years ago

7 0

Answer:

to eat a proper Oreo you eat it like a sandwich.

Step-by-step explanation:

ruslelena [56]3 years ago

5 0

Take apart the chocolate parts and eat the filling I hate chocolate

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Which is the graph of f(x) = -(x + 3)(x + 1)?

Furkat [3]

Answer:

It's the second option

Step-by-step explanation:

Graph for -(x+3)(x+1)

4 0

3 years ago

1.3 ½ days=______hrs.

spayn [35]

1) 84 hours
2) 2.4 meters
3) 4800 seconds
4) 100000grams
5)219.2 Fahrenheit degrees

8 0

3 years ago

Find the fifth roots of 243(cos 240° + i sin 240°).

Mazyrski [523]

Answer:

See below.

Step-by-step explanation:

Fifth root of 243 = 3,

Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),

then r^5( cos Ф + i sin Ф )^5 = 243(cos 240 + i sin 240).

Equating equal parts and using de Moivre's theorem:

r^5 =243 and cos 5Ф + i sin 5Ф = cos 240 + i sin 240

r = 3 and 5Ф = 240 +360p so Ф = 48 + 72p

So Ф = 48, 120, 192, 264, 336 for 48 ≤ Ф < 360

So there are 5 distinct solutions given by:

3(cos 48 + i sin 48),

3(cos 120 + i sin 120),

3(cos 192 + i sin 192),

3(cos 264 + i sin 264),

3(cos 336 + i sin 336).. (Answer).

7 0

3 years ago

The diameter of a sphere is 2,160 mm. The diameter of a second sphere is 7,520 mm. Approximately how many times larger is the vo

fgiga [73]

Answer:

Approximately 42 times larger

Step-by-step explanation:

The diameter of a sphere is 2,160 mm.

The diameter of a second sphere is 7,520 mm.

To see how many times larger is the diameter of second sphere is than the diameter of the second sphere, we divide to get:

$k = \frac{7520}{2160}$

$k = 3.481$

To see how many times larger the volume is, we cube both sides

${k}^{3} = {3.481}^{3}$

This implies that

${k}^{3} = 42.181$

Therefore the volume of the second sphere is approximately 42 times larger

3 0

3 years ago

Greg swam 4 kilometers against the current in the same amount of time it took him to swim 16 kilometers with the current. The ra

ad-work [718]

Answer:

5 kmph

Step-by-step explanation:

Given: Greg swam 4 kilometers against the current.

Greg swam 16 kilometers with the current.

Rate of the current was 3kmph.

Lets assume the speed of greg swimming with no current be "x".

∴ Speed of swimming against current= $(x-3)\ kmph$

Speed of swimming with current= $(x+3)\ kmph$

As given, it took same amount of time to swim both with current and against current.

∴ Forming an equation to find the value of x, which is speed of greg swimming with no current.

We know, $Time= \frac{Distance}{Speed}$

⇒ $\frac{4}{(x-3)} = \frac{16}{(x+3)}$

Multiplying both side by (x+3) and (x-3)

⇒ $4\times (x+3)= 16\times (x-3)$

Using distributive property of multiplication.

⇒ $4x+12= 16x-48$

Subtracting both side by 4x and adding by 48.

⇒ $60= 12x$

Dividing both side by 12

⇒ $x= \frac{60}{12} = 5\ kmph$

Hence, Greg can swim at the rate of 5kmph with no current.

7 0

4 years ago