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LUCKY_DIMON [66]
3 years ago
5

If a car changes its velocity from 32 km/hr to 54 km/hr in 8.0 seconds, what is its acceleration?

Mathematics
2 answers:
densk [106]3 years ago
6 0
2.8 km/hr/sec, B is the answer
Greeley [361]3 years ago
3 0
The correct answer is 2.8 i know this is correct because i have already turned it in.
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What is the mode of the set numbers?: 8, 9, 2, 12, 12, 10, 14, 14, 5​
Maksim231197 [3]
The number 12 and 14 are the modes .
8 0
3 years ago
What is the area of a circle with a diameter of 15. 8cm? To the nearest hundredth
klio [65]

Answer:

see below

Step-by-step explanation:

First we need to find the radius

r =d/2 = 15.8/2 = 7.9 cm

The area of a circle is given by

A = pi r^2

   = pi ( 7.9) ^2

   =62.41 pi

Using 3.14 for pi

195.9674  

To the nearest hundredth

195.97

Using the pi button

196.0667975

To the nearest hundredth

196.07

7 0
2 years ago
Helpppo:)))))) pleaseeee
velikii [3]

Answer:

32

Step-by-step explanation:

Step 1: Define

f(x) = 3x² - 5x - 4

g(x) = -4x - 12

Step 2: Find f(g(x))

f(g(x)) = 3(-4x - 12)² - 5(-4x - 12) - 4

f(g(x)) = 3(16x² + 96x + 144) + 20x + 60 + 4

f(g(x)) = 48x² + 288x + 432 + 20x + 64

f(g(x)) = 48x² + 308x + 496

Step 3: Find f(g(-4))

f(g(-4)) = 48(-4)² + 308(-4) + 496

f(g(-4)) = 48(16) - 1232 + 496

f(g(-4)) = 768 - 736

f(g(-4)) = 32

3 0
3 years ago
Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma
Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with \mu = 112 inches and \sigma = 14 inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - \mu = 112 inches

Standard deviation - \sigma = 14 inches

The z-score formula is given by, Z=\frac{x-\mu}{\sigma}

Now,

P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})

P(X>140)=P(Z>\frac{140-112}{14})

P(X>140)=P(Z>\frac{28}{14})

P(X>140)=P(Z>2)

P(X>140)=1-P(Z

The Z-score value we get is from the Z-table,

P(X>140)=1-0.9772

P(X>140)=0.0228

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

5 0
3 years ago
What percentage of the rectangular sheets of cardboard will be wasted because it is not part of the box and will be discarded wh
irina1246 [14]
Hi Cuppykitty!!

30% I believe because we still have those to rectangles on the side



Hope this helps :)
8 0
3 years ago
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