4b - 6b + 19
Answer : -2b + 19
Answer:
P ( -1 < Z < 1 ) = 68%
Step-by-step explanation:
Given:-
- The given parameters for standardized test scores that follows normal distribution have mean (u) and standard deviation (s.d) :
u = 67.2
s.d = 4.6
- The random variable (X) that denotes standardized test scores following normal distribution:
X~ N ( 67.2 , 4.6^2 )
Find:-
What percent of the data fell between 62.6 and 71.8?
Solution:-
- We will first compute the Z-value for the given points 62.6 and 71.8:
P ( 62.6 < X < 71.8 )
P ( (62.6 - 67.2) / 4.6 < Z < (71.8 - 67.2) / 4.6 )
P ( -1 < Z < 1 )
- Using the The Empirical Rule or 68-95-99.7%. We need to find the percent of data that lies within 1 standard about mean value:
P ( -1 < Z < 1 ) = 68%
P ( -2 < Z < 2 ) = 95%
P ( -3 < Z < 3 ) = 99.7%
Answer:
The total amount of gross profit is 1,490,400
Step-by-step explanation:
1242000 x 1.20 =1,490,400
Hope I helped :)
Answer:
Well it sounds like you are doing volume so it is length time winth time high so times all the fraction
Step-by-step explanation:
The (assumed) answer to this question is no, his mean is $88.67 and his average mean he chose was $92. (Answer inconclusive due to asked question failing to repeat desired answer.)
