Answer:
a) P(B'|A) = 0.042
b) P(B|A') = 0.625
Step-by-step explanation:
Given that:
80% of the light aircraft that disappear while in flight in a certain country are subsequently discovered
Of the aircraft that are discovered, 63% have an emergency locator,
whereas 89% of the aircraft not discovered do not have such a locator.
From the given information; it is suitable we define the events in order to calculate the probabilities.
So, Let :
A = Locator
B = Discovered
A' = No Locator
B' = No Discovered
So; P(B) = 0.8
P(B') = 1 - P(B)
P(B') = 1- 0.8
P(B') = 0.2
P(A|B) = 0.63
P(A'|B) = 1 - P(A|B)
P(A'|B) = 1- 0.63
P(A'|B) = 0.37
P(A'|B') = 0.89
P(A|B') = 1 - P(A'|B')
P(A|B') = 1 - 0.89
P(A|B') = 0.11
Also;
P(B ∩ A) = P(A|B) P(B)
P(B ∩ A) = 0.63 × 0.8
P(B ∩ A) = 0.504
P(B ∩ A') = P(A'|B) P(B)
P(B ∩ A') = 0.37 × 0.8
P(B ∩ A') = 0.296
P(B' ∩ A) = P(A|B') P(B')
P(B' ∩ A) = 0.11 × 0.2
P(B' ∩ A) = 0.022
P(B' ∩ A') = P(A'|B') P(B')
P(B' ∩ A') = 0.89 × 0.2
P(B' ∩ A') = 0.178
Similarly:
P(A) = P(B ∩ A ) + P(B' ∩ A)
P(A) = 0.504 + 0.022
P(A) = 0.526
P(A') = 1 - P(A)
P(A') = 1 - 0.526
P(A') = 0.474
The probability that it will not be discovered given that it has an emergency locator is,
P(B'|A) = P(B' ∩ A)/P(A)
P(B'|A) = 0.022/0.526
P(B'|A) = 0.042
(b) If it does not have an emergency locator, what is the probability that it will be discovered?
The probability that it will be discovered given that it does not have an emergency locator is:
P(B|A') = P(B ∩ A')/P(A')
P(B|A') = 0.296/0.474
P(B|A') = 0.625
The rotation of the triangle is 270 degrees clockwise, or 90 degrees counterclockwise. Most commonly, clockwise measurements are used when it comes to rotations.
I hope this helped. Let me know if I was correct please.
Answer:
Step-by-step explanation:
I'm assuming you meant to type in
because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to
and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.
The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!
Answers:
x = 72
y = 83
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Explanation:
Angle VFG is 50 degrees. The angle adjacent to this is angle EFG which is 180-50 = 130 degrees.
Angle HDW is 77 degrees. The supplementary angle adjacent to this is 180-77 = 103 degrees which is angle EDH.
Pentagon EFGHD has the following five interior angles
- E = x
- F = 130
- G = 170
- H = 65
- D = 103
Note that angles F = 130 and D = 103 were angles EFG and EDH we calculated earlier.
For any pentagon, the interior angles always add to 180(n-2) = 180(5-2) = 180*3 = 540 degrees.
This means,
E+F+G+H+D = 540
x+130+170+65+103 = 540
x+468 = 540
x = 72
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Now focus your attention on triangle THS
We see that the interior angles are
The angle H is 65 degrees because it's paired with the other 65 degree angle shown. They are vertical angles.
For any triangle, the angles always add to 180
T+H+S = 180
y+65+32 = 180
y+97 = 180
y = 180-97
y = 83
Answer:
112.98 square units
Step-by-step explanation:
Let's work backwards:
Circumference = 2πr
(37.68)/2π = r
Area = π
Area = π * 
Area = 112.983 square units
