In a city the record monthly high temperature for March is 56°F. The record monthly low temperature for March is -4°F. What is t
he range of temperature for the months of March
1 answer:
If I am correct the range is just the space in between the high and the low so you just at add the two together 56+4=60 degree Fahrenheit
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The question doesn't seem specific enough. If there are options, please list.
Answer:
1 = No 2 = Yes 3 = 1.88
Step-by-step explanation:
Use the permutation formula
nPr = (n!)/((n-r)!)
20P15 = (20!)/((20-15)!)
20P15 = (20!)/(5!)
The final answer is choice A
2x^2-y
Plug in the values.
2(3)^2-(-2)
2(3)^2+2
Exponents first.
2*9+2
18+2
20
The answer is 20.
I hope this helps!
~kaikers
This equation is physically unsolvable, as 12 isn't equal to 9.