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Ray Of Light [21]
2 years ago
6

NEED HELP! The endpoints of WX are W(2,-7) and X(5,-4).

Mathematics
1 answer:
jeyben [28]2 years ago
3 0

Answer:

3√2 or 4.24

Step-by-step explanation:

d(w,x) = √(5-2)² + (-4-(-7))² = √18 = 3√2               (4.24)

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A complete graph of the polynomial function f is provided. Use your knowledge of the domain, range, behavior at each x intercept
Papessa [141]

The graph represents a polynomial graph, and the equation of the polynomial graph is f(x) = -(x + 5)³(x - 2)²

<h3>How to determine the equation?</h3>

From the graph, we have the following observations:

  • The graph has a turning point at x = 2
  • The graph changes the factor of its direction at x = -5

This means that the graph has a multiplicity of 2 at x = 2 and a multiplicity of 3 at x = -5

So, we have:

f(x) = a(x + 5)³(x - 2)²

The curve is inverted,

This means that a < 0

Assume a = -1.

Then, we have:

f(x) = -(x + 5)³(x - 2)²

Hence, the equation of the polynomial graph is f(x) = -(x + 5)³(x - 2)²

Read more about polynomials at:

brainly.com/question/4142886

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3 0
1 year ago
∠ABD is formed by a tangent and a secant intersecting outside of a circle. If minor arc AC = 72° and minor arc CD = 132°, what i
notsponge [240]
<span>you're given both arcs, minor and major, or near and far arcs, all you need to do, is really plug them in</span>

3 0
3 years ago
When the input of the function is -4 what is the output of the function
IceJOKER [234]

Answer:

The output is 5

Step-by-step explanation:

-4 is the input (x value). To find the output, you have to find where -4 is on the line. -4 is on the line when 5 is the y coordinate (output).

8 0
2 years ago
Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x&gt;1
Lera25 [3.4K]
Assuming the function is

f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}

For f(x) to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)
\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)
\iff2=b+c

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

f'(x)=\begin{cases}2&\text{for }x1\end{cases}

\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)
\iff2=2b+c

Now we solve for b and c:

\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2
5 0
3 years ago
What is the slope of the line y = -2?
rjkz [21]

Answer:

slope= 0

Step-by-step explanation:

it's a horizontal line

4 0
2 years ago
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