Both will contain the sugar ribose and the base uracil
Let’s assume a wire-hair terrier is a true breed for wire hair with alleles (BB) and a smooth-hair terrier is true breed for smooth hair (bb). Allele B is dominant over its allele b. When these two terrier mated and produce offspring wire-hair terrier and smooth-hair terrier in the ratio 3:1.
Based on this result it can be inferred that –
a. The pattern of inheritance is monohybrid cross.
b.Genotype of wire-hair terrier (1BB and 2 Bb) and genotype of smooth-hair terrier is (bb)
c. Phenotype ratio will be 3:1 and genotypic ratio will be 1:2:1.
Answer:
like a cafeteria
Explanation: I did something like this a few days ago
One example is using tree rings on a tree to determine the absolute time
