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shutvik [7]
3 years ago
11

Wally had two more marbled than ashan and together they have 88 marbles how many marbles does ashan have

Mathematics
2 answers:
labwork [276]3 years ago
5 0
Represent as
w=wally
a=ashan
so wally has 2 more marbles than ashan
w=2+a

together they have 88
w+a=88

since w=2+a, subsitute (2+a) for w in the w+a=88 equation
2+a+a=88
add like terms
2+2a=88
subtract 2 from both sides
2a=86
divide by 2
a=43

ashan has 43 marbles
Naily [24]3 years ago
4 0
The obvious answer would be 86, but you have to look closely at the problem. If Wally had two more marbles than Ashan, then that would mean Wally has 45. If Ashan has 86 then that is incorrect because Wally only has two, not two more than Ashan. If Wally has 45, then 80-45 is 43. This equation now makes sense because Wally has two more marbles than ashen, so Wally has 45 marbles and Ashan has 43.
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Please Help! Show all the steps!
likoan [24]

You can start by subtracting different equations from each other.

3x + 2y + 3z = 1

subtract

3x + 2y + z = 7

2z = -6

divide by 2

z = -3

add the following two expressions together:

3x + 2y + z = 7

3x + 2y + 3z =1

6x + 4y + 4z = 8

subtract the following two expressions:

6x + 4y + 4z = 8

5x + 5y + 4z = 3

x - y = 5

^multiply the whole equation above by 3

3x - 3y = 15

subtract the following two expressions:

3x - 3y = 15

3x + 2y = 10

-5y = 5

divide each side by -5

y=-1

take the following expression from earlier:

x - y = 5

substitute y value into above equation

x - - 1 = 5

2 negatives make a positive

x + 1 = 5

subtract 1 from each side

x = 4

Therefore x = 4, y = -1, z = -3

I checked these with all 3 equations and they worked :)

(it's quite complicated, comment if you don't understand anything) :)

7 0
3 years ago
A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading
Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

So, Force = 6089 * 4.4482N

Force = 27085.09 N

b.

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0
3 years ago
14 = 31.7 – 3x What is the solution
netineya [11]
14 = 31.7 - 3x
-17.7 = -3x
x = 5.9


4 0
3 years ago
Read 2 more answers
If a polygon has eight sides then it is an octagon. True or False
Mama L [17]
This is true because octa- means 8
7 0
3 years ago
PQRS IS A TRAPEZIUM IN PQ=16CM ,QR=12CM RS=8CM AND PQR=30° CALCULATE THE AREA OF PQRS​
Nikolay [14]

Answer:

The answer is in a picture

And♤ merry Christmas♡

Step-by-step explanation:

5 0
2 years ago
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