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shutvik [7]
3 years ago
11

Wally had two more marbled than ashan and together they have 88 marbles how many marbles does ashan have

Mathematics
2 answers:
labwork [276]3 years ago
5 0
Represent as
w=wally
a=ashan
so wally has 2 more marbles than ashan
w=2+a

together they have 88
w+a=88

since w=2+a, subsitute (2+a) for w in the w+a=88 equation
2+a+a=88
add like terms
2+2a=88
subtract 2 from both sides
2a=86
divide by 2
a=43

ashan has 43 marbles
Naily [24]3 years ago
4 0
The obvious answer would be 86, but you have to look closely at the problem. If Wally had two more marbles than Ashan, then that would mean Wally has 45. If Ashan has 86 then that is incorrect because Wally only has two, not two more than Ashan. If Wally has 45, then 80-45 is 43. This equation now makes sense because Wally has two more marbles than ashen, so Wally has 45 marbles and Ashan has 43.
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1: square root of 2
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3: square root of 3, squared
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hopefully this helps you :)
6 0
3 years ago
You are planning a trip to the city. The distance is 270 miles. If you drive at an average speed of 45 mph and you leave at 1:30
Agata [3.3K]
First let's find how many hours it will take to get there. 
270/45 = 6
It will take 6 hours to get there. 

6 hours past 1:30 is 7:30.

The answer is 7:30 p.m.

Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)
6 0
3 years ago
An ordinary fair die is a cube with the numbers one through six on the sides represented by painted that. Imagine that such a di
Solnce55 [7]

Answer:

ok so what i think your trying to ask is if we roll two dice that the sum will be more then 6

Two dice

Assuming that the dice are unbiased or not " loaded".

Each side has the same probability, is 1/6 =0.16667, to turn up when rolled, if the die (D) is unbiased. The probability of a side turning up on D1 when 2 dice ( D1,D2) are rolled, is independent of the side turning up in D2. So this is an independent event.

How many ways can one get a sum total of 6 if D1 &D2 are rolled at the same time?

These are the possibilities

Case 1.

D1 =1 & D2=5

Or

D1= 5 & D2=1

Case 2.

D1 =2 & D2=4

Or

D1= 4 & D2= 2

Case 3. D1=3, D2=3

P3 =0.027778

Let's say, P 1 the probability for case 1 and P2 for case 2. There are no other cases.

The final probability P and is the sum total P = P1 + P2 + P3 the probability law of mutually exclusive events.

P1= 0.02778+ 0.02778 =0.055558

P2= 0.02778+0.02778 =0.055558

Same way,

P3=0.027778, when there is only one way to get the sum 6.

So, P = 0.138894

Based on truncating at the sixth decimal place.

A visual representation with two unbiased dice and the possible cases would also give the same result and is a short cut method. I like to derive from the basics.

Hope This Helps!!!

6 0
2 years ago
Keeping in mind the rules for significant figures, determine how many milliliters there are in 0.073 gallons. 1 gallon = 4 quart
andreev551 [17]

we are given

there are in 0.073 gallons

we can see that there are two non-zero places after decimals

so, there are two siginificant figures

step-1: Change gallons to quarts

we know that

1 gallon = 4 quarts

so, we can write as

0.073gallons=0.073*1gallon

0.073gallons=0.073*4quarts

0.073gallons=0.292quarts

step-2: Change into liter

0.073gallons=0.292quarts

we know that

1 liter = 1.057 quarts

or

1 quart=\frac{1}{1.057} litre

0.073gallons=0.292*1quarts

0.073gallons=0.292*\frac{1}{1.057} litre

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step-3: Change into millilitre

we know that

1L=1000mL

0.073gallons=0.27625*1 litre

0.073gallons=0.27625*1000 mL

Since, it is asking for only two significant figures

so, we can also write as

0.073gallons=0.28*1000 mL

0.073gallons=280 mL...................Answer


3 0
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5y - 25x =10 <br><br><br> I need someone to help me solve this asap
ruslelena [56]

Answer:slope=10.000/2.000=5.000

x-intercept=2/5=minus 0.40000

y-intercept=2/1=2.00000

Step-by-step explanation:

8 0
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