R = 11-2m
S = n+5
T = -m-3n+8
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Add up S and T to get...
S+T = (n+5)+(-m-3n+8)
S+T = n+5-m-3n+8
S+T = -m+(n-3n)+(5+8)
S+T = -m+(1n-3n)+(5+8)
S+T = -m+(-2n)+(13)
S+T = -m-2n+13
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Subtract that result from R
R - [S + T]
11-2m - [-m-2n+13]
11-2m +m+2n-13
(-2m+m) + (2n) + (11-13)
(-2m+1m) + (2n) + (11-13)
(-1m) + (2n) + (-2)
-m + 2n - 2
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The final answer is -m + 2n - 2
Answer:
3*104=312
15*108=1620
1620/312=5.19230769 OR 5.19 OR 5.1 OR 5
Answer:
3.6 qt. and 2.4 qt respectively
Step-by-step explanation:
Let x be x% of 50% saline solution. And (100-x%) be the percentage of 60% saline solution.
54=x*(50/100)+(100-x)*(60/100), solving it we will get x=60%. So we need 3.6 qt. of 50% saline solution and 2.4 qt. of 60% saline solution
The answer is C, good luck
