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Lostsunrise [7]
4 years ago
12

What is the reference angle of -3 radians? Explain.

Mathematics
1 answer:
Korolek [52]4 years ago
8 0

Reference angle of -3 radians is α= - 171° 53 min 15 sec .

We know the formula for calculating circular arc

Let l=circular arc which ic according to central angle of the circle α

l=((2R π)/360)α  Let l=1 radian and R=1 (unit circle with radius R=1)

1= ((2π)/360)α => α= 360/(2π)= 180/π= 57° 17 min 45sec

Angle of the 1 radian is equal to angle 57° 17min 45sec

According to this

angle of the  -3 radians = -3 ( 57° 17min 45sec) = - 171° 53min 15sec

when you count in the clockwise direction.

Good luck!!!


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Find the equation of the line passing through the point (4,−1) that is parallel to the line 2x−3y=9.
motikmotik

Hey there!

Line passes through (4, -1) & is parallel to 2x -3y=9

Let's start off by identifying what our slope is. In the slope-intercept form y=mx+b, we know that "m" is our slope.

The given equation needs to be converted into slope-intercept form and we can do this by getting y onto its own side of the equal sign.

Start off by subtracting 2x from both sides.

-3y = -2x + 9

Then, divide both sides by -3.

y = (-2x + 9)/-3

Simplify.

y = 2/3x - 3

"M" is simply a place mat so if we look at our given line, the "m" value is 2/3. Therefore, our slope is 2/3.

We should also note that we're looking for a line that's parallel to the given one. This means that our new line has the same slope as our given line. Therefore, our new line has a slope of 2/3.

Now, we use point-slope form ( y-y₁=m(x-x₁) ) to complete our task of finding a line that passes through (4, -1). Our new slope is 2/3 & it passes through (4, -1).

y-y₁=m(x-x₁)

Let's start by plugging in 2/3 for m (our new slope), 4 for x1 and -1 for y1.

y - (-1) = 2/3(x - 4)

Simplify.

y + 1 = 2/3 + 8/3

Simplify by subtracting 1 from both sides.

y = 2/3x + 8/3 - 1

Simplify.

y = 2/3x + 5/3

~Hope I helped!~

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Step-by-step explanation:

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