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makvit [3.9K]
3 years ago
7

In a video game, Val scored 30%

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
8 0
If he scored 30% less points than Peeta 30% of 1060= 318  1060-318=742 hopefully this helps
LenaWriter [7]3 years ago
4 0

Answer:

742

Step-by-step explanation:

30% of 1060 = 318

1060 - 318 = 742

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PLZZ HELP MEEEEEEEEEE
Nuetrik [128]
The second one is B
7 0
4 years ago
What is the measure of m?<br> 6<br> 3<br> 18<br> n<br> m =<br> =<br> [?]
torisob [31]

Answer:

6/n = n/18

n^2 = 108

n = sqrt 108

a^2 + b^2 = c^2

36 + 108 = m^2

144 = m^2

m=12

Let me know if this helps!

3 0
3 years ago
A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop
attashe74 [19]

Answer:

0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286

0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562

The 99% confidence interval would be given by (0.286;0.562)

Step-by-step explanation:

Information given:

X= 36 represent the families owned at least one DVD player

n= 85 represent the total number of families

\hat p=\frac{36}{85}= 0.424 represent the estimated proportion of families owned at least one DVD player

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286

0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562

The 99% confidence interval would be given by (0.286;0.562)

8 0
3 years ago
An=2n-3 find the first five terms of the sequence
katen-ka-za [31]

Answer:

-1 , 1 , 3 , 5 , 7

Step-by-step explanation:

An = = 2n - 3

n = 1;       A1 = 2*1 - 3  =  2 - 3 = -1

n =2;      A2 = 2*2 - 3 =  4 - 3 = 1

n = 3;     A3 = 2*3 - 3 =  6 - 3 = 3

n= 4;      A4 = 2*4 - 3 =  8 - 3 = 5

n = 5;     A5 = 2*5 - 3 = 10 - 3 = 7

3 0
3 years ago
Evaluate the expression (x-2y)^2where x=3and y=2
zimovet [89]
X = 3

y = 2

(x-2y)^2 = (3-(2*2))^2 = (3-4)^2 = (-1)^2 = -1*-1 = 1

Hence, the answer is 1.
6 0
4 years ago
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